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3 years ago

2x+2y=8 pleaseee help!!

Mathematics

1 answer:

Charra [1.4K]3 years ago

5 0

Answer: x = - y + 4

Step-by-step explanation: u juss Add -2y to both sides and Step 2: Divide both sides by 2.

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Beth's monthly charge for Internet access y is represented by the function

deff fn [24]

Answer:

y =34.5

Step-by-step explanation:

9 times 2.50 = 22.5 + 12 = 34.5,

so y =34.5

6 0

3 years ago

What is the value of <br> 3 1/4 - 1 7/8 =

wlad13 [49]

Answer:

The answer is 11/8 or 1 3/8

Step-by-step explanation:

First, you can break both fractions down into 3+1/4-1+7/8.

Second, use 3 subtract 1, you will get 2+1/4-7/8.

To subtract 7/8 you have to make both numbers denominator same.

1/4 will multiply by 2 on the top and the bottom.

After that, you will get 2 2/8-7/8.

2x8=16, 16+2=18

18/8-7/8=11/8 or 1 3/8

I know its gonna be confusing, but this is all I can do, sorry about that. :)

6 0

4 years ago

Determine the IQR of this data then indicate whether the data set contains any outliers . Explain how you determined this

slega [8]

Place the values in ascending order first:

4, 10, 10, 11, 12, 12, 12, 12, 13, 13, 15, 15, 17, 18, 19, 20

There are 16 values

IQR is 3/4th term - 1/4th term

The 12th value is 15 while the 4th value is 11

Therefore IQR = 15-11 which is 4

I would say the outlier is 4.

Justification: Figure out the mean with the value of 4 then discount it to see whether the mean is affected by the outlier.

6 0

3 years ago

The sum of two angle measures 130 degrees. The difference in the two angle measures is 12 degrees. What are the two angle measur

san4es73 [151]

Answer:

59°, 71°

Step-by-step explanation:

This is a "sum and difference" problem. All problems of this type have the same answer: the larger of the two numbers is the average of those given.

Then the larger angle is (130 +12)°/2 = 71°. The smaller is 71° -12° = 59°.

_____

<em>More detailed solution</em>

There are several ways to get there using equations. You can, for example, let L represent the larger number. Then L - D will be the smaller one (where D represent the difference). The sum of the two numbers (S) is ...

L + (L -D) = S

2L = S + D . . . . collect terms, add D

L = (S+D)/2 . . . the larger number is the average of the sum and difference

5 0

3 years ago

A store sells 8 colors of balloons with at least 28 of each color. How many different combinations of 28 balloons can be chosen?

Len [333]

Answer:

(a) $Selection = 6724520$

(b) $At\ most\ 12 = 6553976$

(c) $At\ most\ 8 = 6066720$

(d) $At\ most\ 12\ red\ and\ at\ most\ 8\ blue = 5896638$

Step-by-step explanation:

Given

$Colors = 8$

$Balloons = 28$ --- at least

Solving (a): 28 combinations

From the question, we understand that; a combination of 28 is to be selected. Because the order is not important, we make use of combination.

Also, because repetition is allowed; different balloons of the same kind can be selected over and over again.

So:

$n => 28 + 8-1$ $= 35$

$r = 28$

$Selection = ^{35}^C_{28$

$Selection = \frac{35!}{(35 - 28)!28!}$

$Selection = \frac{35!}{7!28!}$

$Selection = \frac{35*34*33*32*31*30*29*28!}{7!28!}$

$Selection = \frac{35*34*33*32*31*30*29}{7!}$

$Selection = \frac{35*34*33*32*31*30*29}{7*6*5*4*3*2*1}$

$Selection = \frac{33891580800}{5040}$

$Selection = 6724520$

Solving (b): At most 12 red balloons

First, we calculate the ways of selecting at least 13 balloons

Out of the 28 balloons, there are 15 balloons remaining (i.e. 28 - 13)

So:

$n => 15 + 8 -1 = 22$

$r = 15$

Selection of at least 13 =

$At\ least\ 13 = ^{22}C_{15}$

$At\ least\ 13 = \frac{22!}{(22-15)!15!}$

$At\ least\ 13 = \frac{22!}{7!15!}$

$At\ least\ 13 = 170544$

Ways of selecting at most 12 =

$At\ most\ 12 = Total - At\ least\ 13$ --- Complement rule

$At\ most\ 12 = 6724520- 170544$

$At\ most\ 12 = 6553976$

Solving (c): At most 8 blue balloons

First, we calculate the ways of selecting at least 9 balloons

Out of the 28 balloons, there are 19 balloons remaining (i.e. 28 - 9)

So:

$n => 19+ 8 -1 = 26$

$r = 19$

Selection of at least 9 =

$At\ least\ 9 = ^{26}C_{19}$

$At\ least\ 9 = \frac{26!}{(26-19)!19!}$

$At\ least\ 9 = \frac{26!}{7!19!}$

$At\ least\ 9 = 657800$

Ways of selecting at most 8 =

$At\ most\ 8 = Total - At\ least\ 9$ --- Complement rule

$At\ most\ 8 = 6724520- 657800$

$At\ most\ 8 = 6066720$

Solving (d): 12 red and 8 blue balloons

First, we calculate the ways for selecting 13 red balloons and 9 blue balloons

Out of the 28 balloons, there are 6 balloons remaining (i.e. 28 - 13 - 9)

So:

$n =6+6-1 = 11$

$r = 6$

Selection =

$^{11}C_6 = \frac{11!}{(11-6)!6!}$

$^{11}C_6 = \frac{11!}{5!6!}$

$^{11}C_6 = 462$

Using inclusion/exclusion rule of two sets:

$Selection = At\ most\ 12 + At\ most\ 8 - (12\ red\ and\ 8\ blue)$

$Only\ 12\ red\ and\ only\ 8\ blue\ = 170544+ 657800- 462$

$Only\ 12\ red\ and\ only\ 8\ blue\ = 827882$

$At\ most\ 12\ red\ and\ at\ most\ 8\ blue = Total - Only\ 12\ red\ and\ only\ 8\ blue$

$At\ most\ 12\ red\ and\ at\ most\ 8\ blue = 6724520 - 827882$

$At\ most\ 12\ red\ and\ at\ most\ 8\ blue = 5896638$

3 0

3 years ago