15 - (-3) - 4 -16 22 -8 14

1 answer:

8 0

In this equation, you have to treat the number in the bracket first on the basis of BODMAS
15 - [-3]- 4
Note that when two minuses come together the product is a plus sign.
15 +3 - 4
You have to add before you subract
18 - 4 =14
Therefore, 15- [-3] - 4 = 14.

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Two 6-sided dice are rolled. what is the probability that the sum of the two numbers on the dice will be greater than 9?

AVprozaik [17]

What combination of numbers are needed in order to get a sum of 9?
It can be:
• First die is 6 , second die is 3
• First die is 3 , second die is 6
• First die is 4 , second die is 5
• First die is 5 , second die is 4

How many possible combinations are made? Yep, 4 possible combinations.

Recall the formula for probability
$Probability = \frac{Number of desired outcomes}{Number of all possible outcomes}$

There are 4 desired number of outcomes.
How about the total possible outcomes?
• How many numbers are possible to appear when the first die is rolled?
Answer: 6
• What about the second die?
Answer: Also 6
• Therefore, total possible outcomes = 6 * 6 = 36 outcomes

You can now solve for the probability.

$Probability = \frac{4}{36} = \frac{1}{9}$ or approximately 11.11%