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Oxana [17]
3 years ago
15

Can someone help me figure this out plz? Thank you!!!

Mathematics
1 answer:
Lina20 [59]3 years ago
5 0
5\ \textless \ 2-3y\ \textless \ 14\qquad|-2\\\\5-2\ \textless \ 2-3y-2\ \textless \ 14-2\\\\3\ \textless \ -3y\ \textless \ 12\qquad|:(-3)\\\\-1\ \textgreater \ y\ \textgreater \ -4\\\\\boxed{-4\ \textless \ y\ \textless \ -1}

Answer b.
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Write the equation of a line that goes through the points (-7,10) and (1,4)
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I’m pretty sure the answer is y=3/4x-13/4
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Find the sum of the interior angle measure of a regular polygon with 20 sides
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3240°

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2 years ago
find the zeros of 2x^2 - 16x + 27 using the quadratic formula. be sure to simplify the expression. Can someone please show me ho
____ [38]
For a quadratic of the form f(x)=ax^2+bx+c, we have the quadratic formula 
x=\dfrac{-b \pm \sqrt{b^2 -4ac}  }{2a},
where a is the coefficient (number before the variable) of the squared term, b is the coefficient of the linear term, and c is the constant term.

So, given 2x^2-16x+27=0, we can get that a=2, \ b=-16, and c=27. We substitute these numbers into the quadratic formula above.

x=\dfrac{-(-16) \pm \sqrt{(-16)^2 -4(2)(27)} }{2(2)}

x=\dfrac{16 \pm \sqrt{(256 -216)} }{4}

x=\dfrac{16 \pm \sqrt{40} }{4}

x=\dfrac{16 \pm 2\sqrt{10} }{4}

x=4+ \frac{\sqrt{10}}{2}, \ x=4- \frac{\sqrt{10}}{2}

This is our final answer.

If you've never seen the quadratic formula, you can derive it by completing the square for the general form of a quadratic. Note that the \pm symbol (read: plus or minus) represents the two possible distinct solutions, except for zero under the radical, which gives only one solution.
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3 years ago
PLEASE PLEASE HELP IF YOU KNOW!! THANK YOU
Vladimir [108]
I'm guessing this is what the question is asking?

5 0
3 years ago
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