Because a rectangular pyramid's base is square, the cross section would be as well
R(t) = 4t
A(r) = π(r^2)
a) A(t) = A[r(t)] = π[r(t)]^2 = π[4t]^2 = 16π(t^2)
b) t = 4,
A(4) = 16*3.14*(16)^2 = 12,861.44
Your answer is incorrect. You forgot to get the square root of 25 and 4. Answer should be 16√2
we can only subtract radicals that are the same. At first glance, 4√50 - 2√8 are not the same, so they are not likely to be subtracted. However, each radical can still be simplified.
4 √50 = 4 √25 * 2 = 4 * 5 √2 = 20 √2
2 √8 = 2 √4 * 2 = 2 * 2 √2 = 4 √2
Now that the radicals are the same. then you can subtract the numbers.
20 √2 - 4 √2 = 16√2
1.= 1
2.= -15
3.= -18
4.= -1
5. = -11
6. = 22
Explanation: The sum<span> of the measure of the </span>internal<span> angles of any triangle is 180o . In a right angled triangle, one angle will be 90o . Since we know the measure of one of the other acute (less than 90o ) angles, we subtract the </span>sum<span> of the two known angles from 180 to calculate the measure of the other acute angle.</span>
