I need help with #6!! ASAP

Tom earned $72 walking dogs for 6 hours. How many total hours will it take tom to earn $96 in all? Solve using unit rates

slava [35]

Answer:

8 hours

Step-by-step explanation:

Step one:

Given data

Tom earned $72 walking dogs for 6 hours

amount earned = $72

time taken = 6 hours

Required

The time taken to earn $96

Step two:

let us find the unit rate of his earning

unit rate = 72/6

= 12 per hour

In 1 hour Tom earns $12

in x hours he will earn $96

cross multiply we have

96*1= 12x

divide both sides by 12

x= 96/12

x=8 hours

3 0

3 years ago

26

Triss [41]

Corrected Question

Ping lives at the corner of 3rd Street and 6th Avenue. Ari lives at the corner of 21st Street and 18th Avenue. There is a gym 2/3 the distance from Ping's home to Ari's home. Where is the gym?

9th Street and 10th Avenue
12th Street and 12th Avenue
14th Street and 12th Avenue

15th Street and 14th Avenue

Answer:

(D)15th Street and 14th Avenue

Step-by-step explanation:

Ping's Location: (3rd Street, 6th Avenue)

Ari's Location: (21st Street, 18th Avenue)

The gym is at point P which is $\dfrac{2}{3}$ the distance from Ping's home to Ari's home.

That is, Point P divides the line segment in the ratio 2:1.

We use the section formula:

$(x,y)=\left(\dfrac{mx_2+nx_1}{m+n}, \dfrac{my_2+ny_1}{m+n}\right)$

m:n=2:1, $(x_1,y_1)=(3,6), (x_2,y_2)=(21,18)$

$=\left(\dfrac{2*21+1*2}{2+1}, \dfrac{2*18+1*6}{2+1}\right)\\=\left(\dfrac{45}{3}, \dfrac{42}{3}\right)\\=(15,14)$

The gym is located at 15th Street and 14th Avenue.

6 0

3 years ago

What is the measure of < DBC

notsponge [240]

Answer:

∠D B C = 41°

Step-by-step explanation:

Step(i):-

Given ∠ABC = 90°

In diagram ∠D B C + ∠A B D = 90°

6 x+5 + 8 x +1 = 90

14 x + 6 = 90

14 x = 90 -6

14 x = 84

x = 6

Step(ii):-

∠D B C = 6 x + 5 = 6 (6) +5 = 36 +5 = 41

∠D B C = 41°

∠A B D = 8(6) +1 = 49°

∠D B C + ∠A B D = 41° + 49° = 90°

3 0

3 years ago

Read 2 more answers

HELP!!

Liono4ka [1.6K]

Answer:

Part 1: The polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2: The vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

Step-by-step explanation:

Part 1:

The vertices of the polygon ABCDE are A(2, 8), B(4, 12), C(10, 12), D(8, 8), and E(6, 6).

The vertices of the polygon MNOPQ are M(-2, 8), N(-4, 12), O(-10, 12), P(-8, 8), and Q(-6, 6).

We need to find the transformation or sequence of transformations that can be performed on polygon ABCDE to show that it is congruent to polygon MNOPQ.

The relation between the vertices of ABCDE and MNOPQ are defined as

$(x,y)\rightarrow (-x,y)$