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DENIUS [597]
3 years ago
11

Write 2.9302 as a fraction and a mixed number​

Mathematics
1 answer:
bonufazy [111]3 years ago
8 0

rationalise 29302/100000

=14651/50000

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Lin's teacher uses the box to store her set of cubes with an edge length of one half inch. if the box is completely full, how ma
nlexa [21]

Answer:

448 cubes

Step-by-step explanation:

Volume of cubes fitted in the box will be equal to the cumulative volume of the cubes.

Since, volume of a cube = (Side)³

Side of the cube = \frac{1}{2} inch

Therefore, volume of the cube = (\frac{1}{2})^3=\frac{1}{8} inches

Volume of the storage box = 56 cubic inches

Since, number of cubes fitted in the storage box = \frac{\text{Volume of the storage box}}{\text{Volume of one cube}}

                                                                                 = \frac{56}{\frac{1}{8}}

                                                                                 = 56 × 8

                                                                                 = 448 cubes

Therefore, number of cubes fitted in the storage box = 448

3 0
3 years ago
1 Exam Find the sales tax. Sales Tax Selling Price Rate of Sales Tax Sales Tax $40.00 6% ? The sales tax is $​
Kipish [7]

Answer:

59% why

Step-by-step explanation:

i just took the test my gee

4 0
3 years ago
Read 2 more answers
Work out 2/3 X 2 plz help
Romashka [77]
 \frac{2}{3} × 2
2 = \frac{2}{1}

Numerator × numerator
Denominator × denominator

\frac{2}{3} × \frac{2}{1}
\frac{4}{3}
7 0
3 years ago
manufacturing company produces digital cameras and claim that their products maybe 3% defective. A video company, when purchasin
alexdok [17]

Answer:

P(X>17) = 0.979

Step-by-step explanation:

Probability that a camera is defective, p = 3% = 3/100 = 0.03

20 cameras were randomly selected.i.e sample size, n = 20

Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97

Probability that more than 17 cameras are working P ( X > 17)

This is a binomial distribution P(X = r) nCr q^{r} p^{n-r}

nCr = \frac{n!}{(n-r)!r!}

P(X>17) = P(X=18) + P(X=19) + P(X=20)

P(X=18) = 20C18 * 0.97^{18} * 0.03^{20-18}

P(X=18) = 20C18 * 0.97^{18} * 0.03^{2}

P(X=18) = 0.0988

P(X=19) = 20C19 * 0.97^{19} * 0.03^{20-19}

P(X=19) = 20C19 * 0.97^{19} * 0.03^{1}

P(X=19) = 0.3364

P(X=20) = 20C20 * 0.97^{20} * 0.03^{20-20}

P(X=20) = 20C20 * 0.97^{20} * 0.03^{0}

P(X=20) = 0.5438

P(X>17) = 0.0988 + 0.3364 + 0.5438

P(X>17) = 0.979

The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch

6 0
4 years ago
What is the probability of rolling an odd number on the six-sided cube
tankabanditka [31]
It'd be a 50% chance
7 0
3 years ago
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