Answer:
yes
Step-by-step explanation:
lets use a significance level of = 0.1
<u> Determine if the sequence indicates randomness </u>
First step :
H0 : pattern is random
H1 : pattern not random
n1 ( number of true answers ) = 10
n2 ( number of false answers ) = 10
also number of runs for T = 5
number of runs for F = 5
Total number of runs = 5+ 5 = 10
Given that critical value at 0.05 = 23
we will reject the null hypothesis ( i.e the sequence departs from randomness )
Solving:
-7 + y = 3 + 2y
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Add '-2y' to each side of the equation.
-7 + y + -2y = 3 + 2y + -2y
Combine like terms: y + -2y = -1y
-7 + -1y = 3 + 2y + -2y
Combine like terms: 2y + -2y = 0
-7 + -1y = 3 + 0
-7 + -1y = 3
Add '7' to each side of the equation.
-7 + 7 + -1y = 3 + 7
Combine like terms: -7 + 7 = 0
0 + -1y = 3 + 7
-1y = 3 + 7
Combine like terms: 3 + 7 = 10
-1y = 10
Divide each side by '-1'.
y = -10
Hope it helps. (:
Answer:
You just need to demonstrate that the expression is not equivalent. To do that, we just need to evaluate the expression with a specific number.
For 
, we have
Notice that the answer is true because 2 is not equivalent to 5.
Therefore, the expression is actually non-equivalent.
Answer:
5
Step-by-step explanation:
I hope this helps you out!
