Divide them and then multiply
Hey!!!
Answer is....
diagonals of square bisect each other at right angles.
let diagonal be 2x
Using Pythagoras in a triangle enclosed by a side and 2 half diagonals...




side of a diagonal=2 sqrt50

cm......
HOPE IT HELPS YOU '_'
Answer: The cost of one rose bush is $7 and the cost of one shrub is also $7
Step-by-step explanation:
The situtation can be represented by the systems of the equations.
10x + 4y = 98 x in this case is the cost of one rose bushes
9x + 9y = 126 y is the cost of one shrub.
Solve the system of equation using the elimination method.
10x +4y = 98
9x + 9y = 126 eliminate the y variable so you will have to multiply 9 on top and -4 down.
9(10x +4) = (98)(9)
-4(9x + 9y) = 126(-4)
You will now have the new two systems of equations
90x +36y = 882
-36x +-36y = -504 Now add the equations
0 + 54x = 378
54x = 378
x= 7
Now we know that the cost of one rose bush is 7 so we will plot it into one of the equations and solve for the cost of one shrub.
90(7) +36y=882
630 +36y = 882
-630 -630
36y = 252
y = 7
Check: 10(7) + 4(7)= 98
70 + 28 = 98
98= 98
so one rose bush is actually 7 dollars the same as 1 shrub.
The number 12 and 14 are the modes .