Answer:
Therefore the Area of Rhombus ABCD is 36 unit².
Step-by-step explanation:
Given:
ABCD is a Rhombus
A = (-1,0)
B = (5,-3)
C = (-1,-6)
D = (-7 ,-3)
To Find:
Area of Rhombus ABCD = ?
Solution:
We know that Area of Rhombus is given as
Where ,
d₁ and d₂ are the Diagonals.
We have,
Diagonals as AC and BD,
Using Distance Formula we get
Substituting coordinates A and C we get
Similarly for BD we have,
Now Substituting AC and BD in Formula we get
Therefore the Area of Rhombus ABCD is 36 unit².
Answer:
The sum of the first 47 terms of the given series = 6016
Step-by-step explanation:
Given the sequence
13, 18, 23, ...
An arithmetic sequence has a constant difference 'd' and is defined by
As the difference between all the adjacent terms is the same.
so
Arithmetic sequence sum formula
Put the values
Thus, the sum of the first 47 terms of the given series = 6016
When you represent intervals on the number line, you're including full dots, excluding empty dots, and you're considering numbers highlighted by the line.
In the first case, you've highlighted everything before -2 (full dot, thus included), and everything after 1 (empty dot, excluded). So, the set would be
or, in interval notation,
In the second case, you are looking for all numbers between -3 and 5. This interval is symmetric with respect to 1: you're considering all numbers that are at most 4 units away from 1, both to the left and to the right.
This means that the difference between your numbers at 1 must be at most 4, which is modelled by
where the absolute values guarantees that you'll pick numbers to the left and to the right of 1.