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never [62]
3 years ago
7

Interpreting Algebraic Expressions 11+9k=6n The expressions has 2 terms. True or false?

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
3 0
I believe the expression is true
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Step-by-step explanation:

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In a random sample of students who took the SAT test, 427 had paid for coaching courses and the remaining 2733 had not. Calculat
Dvinal [7]

Answer:

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

427 had paid for coaching courses and the remaining 2733 had not.

This means that n = 427 + 2733 = 3160, \pi = \frac{427}{3160} = 0.1351

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 - 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.1232

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 + 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.147

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

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3 years ago
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