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4 years ago

6

The elevation of a small submarine changes by -38 mile after each exploration. After how many explorations will the submarine's

elevation have changed by -32 miles?

1 answer:

Stella [2.4K]4 years ago

8 0

Answer:

16/19

Step-by-step explanation:

$\frac{1}{-38} =\frac{x}{-32}$

x = 1 / -38 × -32

x = 16 / 19 or 0.8421052632

A full exploration will not be completed

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If Logx (1 / 8) = - 3 / 2, then x is equal to <br> A. - 4 <br> B. 4 <br> C. 1 / 4 <br> D. 10

Agata [3.3K]

<em><u>Answer</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em><em><u> </u></em><em><u>Opti</u></em><em><u>on</u></em><em><u> </u></em><em><u>B</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>co</u></em><em><u>rrect</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em>

x = 4

<em><u>Step</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>step</u></em><em><u> </u></em><em><u>explan</u></em><em><u>ation</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em>

[ <em><u>Ref</u></em><em><u>er</u></em><em><u> to the</u></em><em><u> attachment</u></em> ]

4 0

4 years ago

46.32 - 31.16 rounded

neonofarm [45]

Answer:

15

Step-by-step explanation:

sweet

6 0

3 years ago

Two circles with the same center are congruent sometimes, always, or never ?

love history [14]

I would go with Never because you would have to have two circles with a different center to be congruent

6 0

4 years ago

In the figure, a∥e , m∥n , and m∠3 = 108°. What is the m∠6 ? Enter your answer in the box.

maks197457 [2]

I believe that angle 6 is 108 because I drew to the best of my ability and I see that 3 and 6 are alternate interior angles.

3 0

3 years ago

Ksivusya [100]

Answer:

$m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right]$

Step-by-step explanation:

<u>Calculate the value of m</u>

Given:

$3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]$

Therefore:

$\implies 3=\dfrac{2}{3}m$

$\implies m=3 \times \dfrac{3}{2}$

$\implies m=\dfrac{9}{2}$

<u>Calculate the value of H</u>

Given:

$\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)$

Therefore:

$\implies H= \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]$

<u />

<u>Calculating m × H</u>

<u />

<u /> $\implies m \times H=\dfrac{9}{2} \times \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]$

<u /> $\implies m \times H=\left[\begin{array}{c c c}\dfrac{9}{2}(-2) & \dfrac{9}{2}(8) & \dfrac{9}{2}(-1)\end{array}\right]$

$\implies m \times H=\left[\begin{array}{c c c}-9 & 36 & -\dfrac{9}{2}\end{array}\right]$ <u />

7 0

2 years ago