The area of a triangle is 50 ft?.

In Justin's school 0.825 of the students participate in a sport. If there are 1000 students in Justin's school, how many partici

ikadub [295]

Answer:

825

Step-by-step explanation:

Let the number of students who participated in the sport be x, which is equivalent to 0.825

The total number of students in the school is equivalent to 1

Expressing mathematically,we obtain

0.825:x=1:1000

$\implies \frac{0.825}{x}= \frac{1}{1000}$

By cross multiplying we obtain,

$x=0.825 \times 1000$

We finally simplify to arrive at

$x=825$

Hence the number of students who participated in the sport is 825

8 0

4 years ago

Read 2 more answers

Which equation demonstrates the associative property of multiplication?

kicyunya [14]

Answer:

A

Step-by-step explanation:

The parentheses are switched around, making the answer still the same. However, for Answer choice C, it is Commutative Property because the factors are switched around.

6 0

3 years ago

Read 2 more answers

HEEELLLLPPPPP PLEAAAASE ANSWER QUICK REAL ASSIGNMENT NO FAKE ANSWERS

miv72 [106K]

$- {90u}^{2} \times (2u - 5)$

7 0

3 years ago

Randomly selected 110 student cars have ages with a mean of 8 years and a standard deviation of 3.6 years, while randomly select

monitta

Answer:

1. Yes, there is sufficient evidence to support the claim that student cars are older than faculty cars.

2. The 98% confidence interval for the difference between the two population means is [1.432 years, 3.968 years].

Step-by-step explanation:

We are given that randomly selected 110 student cars to have ages with a mean of 8 years and a standard deviation of 3.6 years, while randomly selected 75 faculty cars to have ages with a mean of 5.3 years and a standard deviation of 3.7 years.

Let $\mu_1$ = mean age of student cars.

$\mu_2$ = mean age of faculty cars.

So, Null Hypothesis, $H_0$ : $\mu_1 \leq \mu_2$ {means that the student cars are younger than or equal to faculty cars}

Alternate Hypothesis, $H_A$ : $\mu_1>\mu_2$ {means that the student cars are older than faculty cars}

(1) The test statistics that will be used here is Two-sample t-test statistics because we don't know about the population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)} {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t_n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean age of student cars = 8 years

$\bar X_2$ = sample mean age of faculty cars = 5.3 years

$s_1$ = sample standard deviation of student cars = 3.6 years

$s_2$ = sample standard deviation of student cars = 3.7 years

$n_1$ = sample of student cars = 110

$n_2$ = sample of faculty cars = 75

Also, $s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(110-1)\times 3.6^{2}+(75-1)\times 3.7^{2} }{110+75-2} }$ = 3.641

So, the test statistics = $\frac{(8-5.3)-(0)} {3.641 \times \sqrt{\frac{1}{110}+\frac{1}{75} } }$ ~ $t_1_8_3$

= 4.952

The value of t-test statistics is 4.952.

Since the value of our test statistics is more than the critical value of t, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we support the claim that student cars are older than faculty cars.

(2) The 98% confidence interval for the difference between the two population means ( $\mu_1-\mu_2$ ) is given by;

98% C.I. for ( $\mu_1-\mu_2$ ) = $(\bar X_1-\bar X_2) \pm (t_(_\frac{\alpha}{2}_) \times s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} })$

= $(8-5.3) \pm (2.326 \times 3.641 \times \sqrt{\frac{1}{110}+\frac{1}{75} })$

= $[2.7 \pm 1.268]$

= [1.432, 3.968]

Here, the critical value of t at a 1% level of significance is 2.326.

Hence, the 98% confidence interval for the difference between the two population means is [1.432 years, 3.968 years].

7 0

3 years ago

Find the complement and supplement of the given angle 43 degrees

densk [106]

Answer:

The complement is 47° and the supplement is 137°.

Step-by-step explanation:

Complementary and Supplementary Angles

When the sum of two angles is equal to 90 degrees, they are called complementary angles. Similarly, if the sum of two angles is 180 degrees, they are called supplementary angles.

We are given an angle of 43 degrees. Its complementary angle is 90° - 43° = 47°, and its supplementary angle is 180° - 43° = 137°.

The complement is 47° and the supplement is 137°.

8 0

3 years ago