Answer:
11.6--------------------------------------
Explanation:
See the attached image for a visual reference
The distance from point D to E is 21 units. Point C is the midpoint, so CD is 10.5 units long (21/2 = 10.5)
We have a right triangle ACD. The legs are
AC = 5
CD = 10.5
The hypotenuse is
AD = x
Because AD is another radius of the same circle
Use the pythagorean theorem to find x
a^2 + b^2 = c^2
5^2 + 10.5^2 = x^2
25 + 110.25 = x^2
135.25 = x^2
x^2 = 135.25
x = sqrt(135.25)
x = 11.629703349613
which rounds to
11.6 when rounding to the nearest tenth (one decimal place)
Step-by-step explanation:
![{x}^{2} - 14x - 25 {y}^{2} + 100y = 76](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20-%2014x%20%20-%2025%20%7By%7D%5E%7B2%7D%20%20%2B%20100y%20%3D%2076)
Factor by grouping,
![( {x}^{2} - 14x) - (25 {y}^{2} - 100y) = 76](https://tex.z-dn.net/?f=%28%20%7Bx%7D%5E%7B2%7D%20%20-%2014x%29%20%20%20-%20%2825%20%7By%7D%5E%7B2%7D%20%20-%20100y%29%20%3D%2076)
Complete the square, with the x variables,
![( {x}^{2} - 14x + 49) - (25 {y}^{2} - 100y) = 125](https://tex.z-dn.net/?f=%28%20%7Bx%7D%5E%7B2%7D%20%20-%2014x%20%2B%2049%29%20%20-%20%2825%20%7By%7D%5E%7B2%7D%20%20-%20100y%29%20%3D%20125)
Factor out 25 for the y variables
![( {x}^{2} - 14x + 49) - 25( {y}^{2} - 4y) = 125](https://tex.z-dn.net/?f=%28%20%7Bx%7D%5E%7B2%7D%20%20-%2014x%20%2B%2049%29%20-%2025%28%20%7By%7D%5E%7B2%7D%20%20-%204y%29%20%3D%20125)
Complete the square
![( {x}^{2} - 14x + 49) - 25( {y}^{2} - 4y + 4) = 25](https://tex.z-dn.net/?f=%28%20%7Bx%7D%5E%7B2%7D%20%20-%2014x%20%2B%2049%29%20-%2025%28%20%7By%7D%5E%7B2%7D%20%20-%204y%20%2B%204%29%20%3D%2025)
Simplify the perfect square trinomial
![(x - 7) {}^{2} - 25(y - 2) {}^{2} = 25](https://tex.z-dn.net/?f=%28x%20-%207%29%20%7B%7D%5E%7B2%7D%20%20-%2025%28y%20-%202%29%20%7B%7D%5E%7B2%7D%20%20%3D%2025)
Make the right side be 1 so divide everything by 25.
![\frac{(x - 7) {}^{2} }{25} - (y - 2) {}^{2} = 1](https://tex.z-dn.net/?f=%20%5Cfrac%7B%28x%20-%207%29%20%7B%7D%5E%7B2%7D%20%7D%7B25%7D%20%20-%20%20%28y%20-%202%29%20%7B%7D%5E%7B2%7D%20%20%3D%201)
Here our center is (7,2).
The answers are C and also D
Answer:
The perimeter is 38.25 units
Step-by-step explanation:
The perimeter of the tra-pezoid is the distance around it.
The length of the bases can be found using the absolute value method.
|RS|=|20-14|=6 units.
|TQ|=|22-8|=14
Recall the distance formula;
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
We use the distance to find the non parallel sides.
units.
and
units.
The perimeter of the tra-pezoid is
=14+10+6+8.25=38.25
Answer:
f(x) -> 2 as x -> -∞ and f(x) -> ∞ as x -> ∞
Step-by-step explanation:
f(x) -> 2 as x -> -∞ and f(x) -> ∞ as x -> ∞
*this is because the graph shows that the y value cannot pass by 2 as the x value constantly decreases and as x is increasing, there is just an arrow showing that the graph is constantly going up and therefore going to ∞