What is the product? a-3/7 divided by 3-a/21

FastForward has net income of $19,090 and assets at the beginning of the year of $209,000. Its assets at the end of the year tot

SVETLANKA909090 [29]

Given:

Net income = $19,090

Assets at the beginning of the year = $209,000.

Assets at the end of the year total = $264,000.

To find:

The return on assets.

Solution:

Formula used:

$\text{Return of assets}=\dfrac{\text{Net income}}{\text{Average of assets at the beginning and at the end}}$

Using the above formula, we get

$\text{Return of assets}=\dfrac{19090}{\dfrac{20900+264000}{2}}$

$\text{Return of assets}=\dfrac{19090}{\dfrac{473000}{2}}$

$\text{Return of assets}=\dfrac{19090}{236500}$

$\text{Return of assets}\approx 0.0807$

The percentage form of 0.0807 is 8.07%.

Therefore, the return on assets is 8.07%.

6 0

3 years ago

Determine whether the improper integral converges or diverges, and find the value of each that converges.

sineoko [7]

Answer:

Since the $\lim_{x\to -\infty} \frac{1}{(x-2)^2}=0$ then we have this:

$\int_{-\infty}^{-1} (x-2)^{-3} dx =-\frac{1}{18}$

And we see that our integral on this case converged to -1/18.

Step-by-step explanation:

For this case we need to determine if the following integral converges or not:

$\int_{-\infty}^{-1} (x-2)^{-3} dx$

We can rewrite the integral like this:

$\int_{-\infty}^{-1} \frac{1}{(x-2)^3} dx$

Then we can use the substitution $u = x-2$ and then $du = dx$ and we have this:

$\int_{-\infty}^{-3} \frac{1}{u^3} du=\int_{-\infty}^{-3} u^{-3} du$

If we solve the integral we got:

$=\frac{u^{-3+1}}{-3+1} =-\frac{u^{-2}}{2}=-\frac{1}{2}\frac{1}{u^2}$

And then the integral would be equal to:

$\int_{-\infty}^{-1} (x-2)^{-3} dx = -\frac{1}{2(x-2)^2}\Big|_{-\infty}^{-1}$

And if we replace and using the fundamental theorem of calculus we got:

$= -\frac{1}{2} [\frac{1}{(-1-2)^2} -\lim_{x\to -\infty} \frac{1}{(x-2)^2}]$

Since the $\lim_{x\to -\infty} \frac{1}{(x-2)^2}=0$ then we have this:

$\int_{-\infty}^{-1} (x-2)^{-3} dx =-\frac{1}{18}$

And we see that our integral on this case converged to -1/18.

5 0

3 years ago

Plz help. show work too

Eddi Din [679]

Answer:

56mm²

Step-by-step explanation:

i will appreciate if u give brainliests, thanks

3 0

3 years ago

Six friends visit a museum to see the new holograms exhibit. the group paid for admission to The museum and $12 for parking. The

Mnenie [13.5K]

X+12 because the 6 refers to the number of friends

6 0

3 years ago

Carlota needs to practice the pianofor 1 2/3 hours. She has been practicing for 3/4 of an hour. how much longer must she practic

Sliva [168]

11/12 hours left. 1 2/3 - 3/4 = 11/12. First, find the common denominator (12) . The problem is now 1 8/12 - 9/12. Use the 1 in (1 8/12) to borrow. Multiply the denominator by 1 (12) and add that to the numerator. The question is now 20/12 - 9/12. I assume that you can finish it off from there.

5 0

3 years ago

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