23+8X is the answer to this problem
substitution and elimination means that you need to use one equation and substitute it in place of some variable in the other equation.
Consider the above two equations.
Take equation 1, which is 4x-2y=22 => x=(22+2y)/4
substitute the x value gained above in equation 2.
so, 2((22+2y)/4)+4y=6
22+2y+8y=12 => 10y = -10 => y= -1.
Substitute y= -1 in x value obtained in the beginning.
So, x= (22 - 2)/4 => 5.
There fore, x= 5 and y= -1
Hope it helps.
Answer:
y²+10z-10y-yz
Reaaranging the terms
=y²-yz+10z-10y
taking common
=y(y-z)+10(y-z)
=(y+10)(y-z) is the right option
i hop this will help you :)
B
The original value will be multiplied by 0.96 each time, making it 4% less than what it was.
