Answer:
B
Step-by-step explanation:
Given
7 + x ≤ 10 ( subtract 7 from both sides )
x ≤ 3 → B
Answer:
2240 scooter
Step-by-step explanation:
725+579+696=2000
2000*1.12=2240
Cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.
<u>Solution:
</u>
Need to calculate
and then multiply the result by ![\sqrt[3]{14903}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B14903%7D)
Let us first evaluate ![\sqrt[3]{1728}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1728%7D)
![\Rightarrow \sqrt[3]{1728}=\sqrt[3]{12 \times 12 \times 12}=12](https://tex.z-dn.net/?f=%5CRightarrow%20%5Csqrt%5B3%5D%7B1728%7D%3D%5Csqrt%5B3%5D%7B12%20%5Ctimes%2012%20%5Ctimes%2012%7D%3D12)
As need to multiply 12 by ![\sqrt[3]{14903}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B14903%7D)
![\Rightarrow 12 \times \sqrt[3]{14903}](https://tex.z-dn.net/?f=%5CRightarrow%2012%20%5Ctimes%20%5Csqrt%5B3%5D%7B14903%7D)
On solving
, we get
![\sqrt[3]{14903}=24.608](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B14903%7D%3D24.608)
![\Rightarrow 12 \times \sqrt[3]{14903}=12 \times 24.608=295.306](https://tex.z-dn.net/?f=%5CRightarrow%2012%20%5Ctimes%20%5Csqrt%5B3%5D%7B14903%7D%3D12%20%5Ctimes%2024.608%3D295.306)
Hence cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.
The first letter can be any one of 5. For each of those . . .
The second letter can be any one of the remaining 4. For each of those . . .
The third letter can be any one of the remaining 3. For each of those . . .
The fourth letter can be any one of the remaining 2. For either of those . . .
The fifth letter is the last remaining one.
Total number of possibilities = (5 x 4 x 3 x 2 x 1) =
<em> 120 ways</em> to line them up.
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makes you cool. Maybe it does make you one of the crowd, but life
is not a war between you and school. School is simply something that
a lot of grown-ups spend a lot of money on, and a lot of teachers spend
their whole life on, to make sure that a lot of kids won't go through <em><u>their</u></em>
whole life stupid. You can learn everything you ever want to know there,
and it's all free. That's a pretty good deal.