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baherus [9]
3 years ago
7

Here are two circles. Their centers are A and F. What is the same about the two circles?

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
8 0

Answer:

The diameter of both is 8.

Step-by-step explanation:

The ratio is 4 of the first circle. And d=2r. So the diameter is 8.

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A rectangle pyramid is sliced parallel to its base as shown in the figure. What is the shape of the resulting two-dimensional cr
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The weight of corn chips dispensed into a 14-ounce bag by the dispensing machine has been identified as possessing a normal dist
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The probability that a normally distributed dataset with a mean, μ, and statndard deviation, σ, exceeds a value x, is given by

P(X\ \textgreater \ x)=1-P(X\ \textless \ x)=1-P\left(z\ \textless \  \frac{x-\mu}{\frac{\sigma}{\sqrt{n}}} \right)

Given that t<span>he weight of corn chips dispensed into a 14-ounce bag by the dispensing machine is a normal distribution with a mean of 14.5 ounces and a standard deviation of 0.2 ounce.

</span>If <span>100 bags of chips are randomly selected the probability that the mean weight of these 100 bags exceeds 14.6 ounces is given by

P(X\ \textgreater \ 14.6)=1-P\left(z\ \textless \  \frac{14.6-14.5}{\frac{0.2}{\sqrt{100}}} \right) \\  \\ =1-P\left(z\ \textless \  \frac{0.1}{\frac{0.2}{10}} \right)=1-P\left(z\ \textless \  \frac{0.1}{0.02} \right) \\  \\ =1-P(z\ \textless \ 5)=1-1=0

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7 0
3 years ago
A school district needs to arrange transportation for at least 360 students for a field trip. The district can use large buses o
Thepotemich [5.8K]

Answer : $1700

From the given information we make constraints

Let x be the number of large buses

and y be the number of small buses

C be the total cost for the trip

Cost C  = 300 * number of large buses + 200 * number of small buses

So C = 300 x + 200 y

Constraints are :

at least 360 students, So 60 x + 45 y >= 360

at most 7 buses , So x + y < = 7

Number of large buses x>=0

Number of large buses y > =0

Now we graph the constraints and find all the endpoints

Graph is attached below

End points are (3,4) , (6,0) and (7,0)

Now we find cost at each end points

C = 300 x + 200 y

(3,4) ----> 300(3) + 200(4) = 1700

(6,0) ----> 300(6) + 200(0) = 1800

(7,0) ----> 300(7) + 200(0) = 2100

The minimum cost is 1700



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Answer:

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Step-by-step explanation:

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2 years ago
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