ANSWER

EXPLANATION
The given equation is:

Group similar terms to obtain:

Simplify similar terms,

Divide both sides by -2.5


Let's solve your system by substitution.
y
=
−
2
x
+
7
;
y
=
5
x
−
7
Step: Solve
y
=
−
2
x
+
7
for y:
y
=
−
2
x
+
7
Step: Substitute
−
2
x
+
7
for
y
in
y
=
5
x
−
7
:
y
=
5
x
−
7
−
2
x
+
7
=
5
x
−
7
−
2
x
+
7
+
−
5
x
=
5
x
−
7
+
−
5
x
(Add -5x to both sides)
−
7
x
+
7
=
−
7
−
7
x
+
7
+
−
7
=
−
7
+
−
7
(Add -7 to both sides)
−
7
x
=
−
14
−
7
x
−
7
=
−
14
−
7
(Divide both sides by -7)
x
=
2
Step: Substitute
2
for
x
in
y
=
−
2
x
+
7
:
y
=
−
2
x
+
7
y
=
(
−
2
)
(
2
)
+
7
y
=
3
(Simplify both sides of the equation)
Answer: x=2 and y=3
Answer:
i)16
ii)9
Step-by-step explanation:
![\sqrt{256} \\=\sqrt{16*16} \\=16\\\\ii)\ \sqrt[3]{729}\\ =\sqrt[3]{9*9*9} \\=9](https://tex.z-dn.net/?f=%5Csqrt%7B256%7D%20%5C%5C%3D%5Csqrt%7B16%2A16%7D%20%5C%5C%3D16%5C%5C%5C%5Cii%29%5C%20%5Csqrt%5B3%5D%7B729%7D%5C%5C%20%3D%5Csqrt%5B3%5D%7B9%2A9%2A9%7D%20%5C%5C%3D9)
Answer:
Rhombus
Step-by-step explanation:
The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).
We use the distance formula to find the length of AB.



The length of AD is



The length of BC is:



The length of CD is



Since all sides are congruent the quadrilateral could be a rhombus or a square.
Slope of AB
Slope of BC 
Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus