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Black_prince [1.1K]
3 years ago
14

there tiger barbs in a 15 gallon aquarium and giant dani is in a 30 gallon aquarium.what numerical expression to represent the g

reatest total number of fish that could be in both aquariums.
Mathematics
1 answer:
Eva8 [605]3 years ago
3 0
The numerical expression that represents the total number is parentheses 15 divided by 3 plus parentheses 30 divided by 5
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A pie chart titled Which Pet Would you Choose: Dog, Cat, or Fish question mark. 50 percent chose a dog, 25 percent chose a cat,
Galina-37 [17]

Answer:

25%

Step-by-step explanation:

It says 25% chose fish.

5 0
3 years ago
Jennifer earns $7.60 per hour working after school. She wants to buy a musical instrument and she needs at least $500. Write an
slega [8]

Answer:

Step-by-step explanation:

let h be the number of hours.

7.60 h≥ 500

76h≥5000

6 0
3 years ago
L
Harlamova29_29 [7]

Answer:

(Z + 2•)

Step-by-step explanation:

5 0
3 years ago
Custom Office makes a line of executive desks. It is estimated that the total cost for making x units of their Senior Executive
Ivan

Answer:

(a) The average cost function is \bar{C}(x)=95+\frac{230000}{x}

(b) The marginal average cost function is \bar{C}'(x)=-\frac{230000}{x^2}

(c) The average cost approaches to 95 if the production level is very high.

Step-by-step explanation:

(a) Suppose C(x) is a total cost function. Then the average cost function, denoted by \bar{C}(x), is

\frac{C(x)}{x}

We know that the total cost for making x units of their Senior Executive model is given by the function

C(x) = 95x + 230000

The average cost function is

\bar{C}(x)=\frac{C(x)}{x}=\frac{95x + 230000}{x} \\\bar{C}(x)=95+\frac{230000}{x}

(b) The derivative \bar{C}'(x) of the average cost function, called the marginal average cost function, measures the rate of change of the average cost function with respect to the number of units produced.

The marginal average cost function is

\bar{C}'(x)=\frac{d}{dx}\left(95+\frac{230000}{x}\right)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g\\\\\frac{d}{dx}\left(95\right)+\frac{d}{dx}\left(\frac{230000}{x}\right)\\\\\bar{C}'(x)=-\frac{230000}{x^2}

(c) The average cost approaches to 95 if the production level is very high.

\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})\\\\\lim _{x\to a}\left[f\left(x\right)\pm g\left(x\right)\right]=\lim _{x\to a}f\left(x\right)\pm \lim _{x\to a}g\left(x\right)\\\\=\lim _{x\to \infty \:}\left(95\right)+\lim _{x\to \infty \:}\left(\frac{230000}{x}\right)\\\\\lim _{x\to a}c=c\\\lim _{x\to \infty \:}\left(95\right)=95\\\\\mathrm{Apply\:Infinity\:Property:}\:\lim _{x\to \infty }\left(\frac{c}{x^a}\right)=0\\\lim_{x \to \infty} (\frac{230000}{x} )=0

\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})= 95

6 0
3 years ago
A girl scout was selling boxes of cookies. In a month, she sold both boxes of chocolate chip cookies ($1.25 each) and boxes of p
Katena32 [7]

Answer:

Number of plain cookie boxes sold = 785 boxes

Step-by-step explanation:

Given: Cost of a chocolate chip cookie box = $1.25

Cost of a plain cookie box = $0.75

Total number of boxes sold = 1585

Total cost of the sold boxes = $1588.75

Let, number of plain cookie boxes sold = x

Number of chocolate chip cookie boxes sold = 1585 - x

So,

Total cost = total cost of the sold plain cookie boxes + total cost of the sold chocolate chip cookie boxes

$1588.75 = x ($0.75) + (1585 - x) ($1.25)

1588.75 = 0.75 x + 1981.25 - 1.25 x

0.5 x = 392.5

Therefore,

<u>Number of plain cookie boxes sold: x = 392.5 ÷ 0.5 = 785 boxes</u>

3 0
3 years ago
Read 2 more answers
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