Given:
The inequality is:

To find:
The solution of the given inequality.
Solution:
We have,

Multiply both sides by 3.

Divide both sides by -8 and change the sign of inequality.


It can be written as:

Therefore, the correct option is A.
As we know that the standard equation of circle is
, where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>
Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>
Now , putting values in our standard equation ;
<em>This is the required equation of </em><em>Circle</em>
Refer to the attachment as well !
Answer:
Step-by-step explanation:
A factor tree is not unique for a given number. Instead of expressing 36 as 2 × 18, we can express 36 as 6 × 6. Prime factorization of 36 using factor tree method is 2 × 2 × 3 × 3 = 2² × 3².
Step-by-step explanation:
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Alright, lets get started.
Jim was thinking of a number.
Suppose the number Jim was thinking, is x.
Jim adds 20 to it means number will be = 
And Jim doubles it, means 
Jim gets 99.2 and as per us, he gets 
So, making them equal


Subtracting 40 in both sides



It means the original number is 29.6. : Answer
Hope it will help :)