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Serhud [2]
3 years ago
12

Which graph below does not represent a

Mathematics
1 answer:
Nastasia [14]3 years ago
7 0

Answer:

I don’t see any graphs. Try copying android pasting images.

Step-by-step explanation:

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You and your four friends are going to a concert. The total price for the tickets was $118.75 which includes a $10 service fee.
Alex787 [66]

Answer:475

Step-by-step explanation:

118.75 is the cost whitch includes a 10$ service fee

118.75x10=475

8 0
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Devin is investigating the relationship between the temperature in degrees Fahrenheit and the number of gallons sold at a lemona
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d. A good line of best fit is y= 0.36x -20.15 because this is what the regression calculator returns if all the data except the point (86, 2) are entered. :)

Step-by-step explanation:

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4 is the repeating digit 
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Alaina went to Applebee's for dinner with some friends.
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Step-by-step explanation:

6 0
2 years ago
Assume the random variable X is normally distributed with mean 53 and standard deviation of 6. Find the 9th percentile
satela [25.4K]

Answer:

<em>The 9th percentile of X is 44.96</em>

Step-by-step explanation:

<u>Percentiles for a Normal Distribution</u>

The standard normal distribution can be used for computing percentiles. For example, the median is the 50th percentile being the center value, the first quartile is the 25th percentile, and so on.

To compute percentiles of a normal distribution we can use the formula

X=\mu+z\sigma

Where \mu is the mean, \sigma is the standard deviation of the variable X, and z is the z-score value from the standard tables

The value of X can also be directly obtained from digital tables included in math packages and tools like Excel.

The Excel NORM.INV Function calculates the inverse of the cumulative Normal Distribution Function for a given value of p, \mu and \sigma.

We'll use the values

p=9\%=0.09,\ \mu=53, \ \sigma=6

NORM.INV(0.09,53,6) results in 44.96 which means the 9th percentile of X is 44.96

We could have used the standard normal distribution, which only needs the value of p

NORM.S.INV( 0.09 )=-1.34

That is the value of z, we now apply the formula

X=\mu+z\sigma

X=53+(-1.34)\cdot 6=44.96

We get the very same result as before

6 0
2 years ago
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