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Marysya12 [62]
3 years ago
15

In a block-style business letter, the paragraphs are double-spaced and indented. True or False

Computers and Technology
2 answers:
Sav [38]3 years ago
5 0
I am pretty sure it is true
larisa [96]3 years ago
5 0

Answer:

False

Explanation:

When preparing a business letter,  we have several layout options. Among them, block style is the most common type of business letter layout.  In a block-style business letter, the entire text within a paragraph is single-spaced and aligned to the left.  We will only see double space appears between the paragraphs but not the text within each of the paragraphs.  

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1. Write Python code to implement the following:
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Answer:

package Lab6Problema;

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{

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}

 

public static void L()//prints L

{

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public static void O()//prints O

{

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public static void W()//prints W

{

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public static void R()//prints R

{

System.out.println();

System.out.println("***** ");

System.out.println("** **");

System.out.println("***** ");

System.out.println("** **");

System.out.println("** **");

}

 

public static void D()//prints D

{

System.out.println();

System.out.println("**** ");

System.out.println("* * ");

System.out.println("* *");

System.out.println("** * ");

System.out.println("**** ");

}

public static void blank() //prints blank space

{

System.out.println();

System.out.println();

System.out.println();

}

public static void main(String[] args) {

//just enter "Hello World" as input as specified

System.out.println("Enter a Message");

Scanner scan=new Scanner(System.in);

String myMessage=scan.nextLine(); // read msg using scanner

int numOfCharacters=myMessage.length();// calculate message lenth

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{

// gets character at position i, and switch accordingly

switch(myMessage.charAt(i))

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case 'H':

case 'h':H();break;

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case 'e':E();break;

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case 'l':L();break;

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case 'o':O();break;

case 'W':

case 'w':W();break;

case 'R':

case 'r':R();break;

case 'D':

case 'd':D();break;

case ' ':blank();break;

}

}

}

}

Explanation:

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Answer:

The Linux command is <em>find</em><em>.</em>

Explanation:

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We can achieve this using the following piece of code (as example):

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<em>Look carefully</em> that <em>one or more</em> embedded spaces is (are) represented in <em>regular expressions</em> using <em>a space </em>before the <em>metacharacter</em> (+),  and characters are represented using the metacharacter (.) before (*), that is, (.*)

In other words, the quantifier (+) represents <em>one or more</em> occurrences (or matches) and quantifier metacharacter (*) zero or more times cases for that evaluation.

So, after testing all files available in the current directory with -regex test, <em>find</em> will execute the action -delete for all files matching the result of such an evaluation (and finally obtaining what we are looking for).

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3 years ago
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