Answer:
(a+5)^2=25 means a^2+5^2=25, a^2=25-25 then a^2=√0, a=0
The trick is to exploit the difference of squares formula,

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

Whatever you do to the denominator, you have to do to the numerator too. So

Expand the numerator:






So we have

But √12 = √(3•4) = 2√3, so

Answer:
ΔT = -75°F
Step-by-step explanation:
ΔT = T₁ - T₀ = 350 - 425 = -75°F
Answer:
2. 
Step-by-step explanation:
2. The line will be parallel to the current track which means they have the same slope. To write the equation, use the slope m=1/2 and the point (2,4) in point slope form:

This is the equation of the line. You can convert it to slope intercept form:
