Angle CED is a right angle, AB congruent to CD, DB bisects AC at E Prove: Quadrilateral ABCD is a Rhombus

1 answer:

4 0

Properties of Rhombus:
1) A flat shape with 4 equal straight sides. It looks like a kite or a diamond.
2) all sides have equal length
3) opposite sides are parallel and opposite angles are equal
4) the diagonals bisect each other at a right angle.
5) the altitude is the distance at right angles to two sides

∠CED is a right angle : GIVEN
AB congruent to CD : all sides have equal length
DB bisects AC at E : diagonals bisect each other at a right angle.

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Q3 -- I'm not completely sure on this one but I think the equation would transfer to this 2*5 + 5*3 + 2*3. So 2*5 is 10, 5*3 is 15, and 2*3 is 6. Add them all together and you get 31.

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3 years ago

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lilavasa [31]

Answer:

$x = r - h$

Step-by-step explanation:

When solving for x, we want to get x all by itself on one side of the equals side. It doesn't matter which side.

In this case, we have x + h. Since we want x alone we have to get rid of the h. We can do this by subtracting h from both sides (whatever you do to one side, you have to do to the other side).

$r = x + h \\ r - h = x + h - h \\ r - h = x$