All categories

3 years ago

Write a formula that will help james find the price per milliliter for each brand

Mathematics

1 answer:

navik [9.2K]3 years ago

7 0

Answer:

$z=\frac{x}{y}$

Step-by-step explanation:

<u><em>The complete question is</em></u>

James has to buy juice for his class party. there are several brands of juice at the store, and each container is a different size and price. write a formula that will help James find the price per milliliter for each brand.

x=price of juice

y=number of milliliters in carton

z=price per milliliter

we know that

The price per milliliter for each brand, is the same that the unit rate

To find out the unit rate , divide the price of juice by the number of milliliters in carton

$z=\frac{x}{y}$

You might be interested in

The slope of the line that passes through the points (-1,w) and (-10,4) is 1/9

forsale [732]

Answer:

Step-by-step explanation:

5 0

3 years ago

I need this answered ASAP !!!! Right answers only

otez555 [7]

This is not a function because they use the same y axis.

8 0

3 years ago

A student at a four-year college claims that mean enrollment at four-year colleges is higher than at two-year colleges in the Un

WINSTONCH [101]

Answer:

Part 1: The statistic

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=35+35-2=68$

Replacing we got

$t=\frac{(5135-4436)-0}{\sqrt{\frac{783^2}{35}+\frac{553^2}{35}}}}=4.31$

Part 2: P value

Since is a right tailed test the p value would be:

$p_v =P(t_{68}>4.31)=0.000022 \approx 0.00002$

Comparing the p value we see that is lower compared to the significance level of 0.01 so then we can reject the null hypothesis and we can conclude that the mean for the four year college is significantly higher than the mean for the two year college and then the claim makes sense

Step-by-step explanation:

Data given

$\bar X_{1}=5135$ represent the mean for four year college

$\bar X_{2}=4436$ represent the mean for two year college

$s_{1}=783$ represent the sample standard deviation for four year college

$s_{2}=553$ represent the sample standard deviation two year college

$n_{1}=35$ sample size for the group four year college

$n_{2}=35$ sample size for the group two year college

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

System of hypothesis

We need to conduct a hypothesis in order to check if the mean enrollment at four-year colleges is higher than at two-year colleges in the United States , the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}\leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

We can assume that the normal distribution is assumed since we have a large sample size for each case n>30. So then the sample mean can be assumed as normally distributed.

Part 1: The statistic

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=35+35-2=68$

Replacing we got

$t=\frac{(5135-4436)-0}{\sqrt{\frac{783^2}{35}+\frac{553^2}{35}}}}=4.31$

Part 2: P value

Since is a right tailed test the p value would be:

$p_v =P(t_{68}>4.31)=0.000022$

6 0

3 years ago

Solve for x and why please using these!!!

krok68 [10]

Answer:

$x = 40$

$y = 5$

Step-by-step explanation:

$4x = 2x+80\\2x = 80\\x = 40$

Edit: Solve for Y

A straight line is 180 degrees so one side (the x side) is 160°, The Y side is 20, and you can work backwards by -

$8y - 20 = 20\\8y = 40\\y = 5$

4 0

3 years ago

Select the correct answer from each drop-down menu.

Hatshy [7]

Answer:

the difference in latitude is 91.22°

the difference in longitude is 147.95°

Step-by-step explanation:

For Liverpool, London. The latitude is 53.41°, longitude is -2.99°

For Melbourne, Australia. The latitude is -37.81°, longitude is 144.96°

The negative or positive magnitude of their values shows their position on either sides of the origin of the latitude (equator) and the origin of the longitude (prime meridian).

The latitude measures the relative position of a point, north or south of the equator (latitude 0°). The longitude measures the relative position, east or west of the prime meridian (longitude 0°)

the difference in latitude is 53.41° - (-37.81°) = 53.41° + 37.81° = 91.22°

the difference in longitude = 144.96° - (-2.99°) = 144.96 + 2.99 = 147.95°

4 0

3 years ago