Answer:
20 ≤ x ≤ 70
Step-by-step explanation:
Given that:
30 ≤ x + 10 ≤ 80
By solving the left half inequality first:
30 ≤ x + 10
Subtracting 10 from both sides:
30 - 10 ≤ x + 10 -10
20 ≤ x
Now solving inequality of right half:
x + 10 ≤ 80
Subtracting 10 from both sides:
x + 10 -10 ≤ 80 - 10
x ≤ 70
So after simplification we get:
20 ≤ x ≤ 70
I hope it will help you!
Each friend will get 16 chips. There is a remainder of 4 chips.
Answer:
D
Step-by-step explanation:
Firstly, since it is a selection question, we shall be using a combination approach.
So here we are trying to select the best answer that describes that 2 out of 10 students are selected.
Let’s consider the scenario below;
selecting r out of n can be resolved using the combination nCr
= n!/(n-r)!r!
Now in this case, our n = 10 and r = 2.
Thus, 10C2, we have ;
10!/(10-2)!2! = 10!/8!2! = (10 * 9 * 8!)/8!2! = (10 *9)/2! = 90/2 = 45
Thus, 10C2 = 45
Here, the order of selection does not matter as we can select in random fashion. This makes option D correct
If you do the proportion, you have to put 1/5 = 20/100. The 20 represents the percentage. Then you have to say to yourself that how many time 5 goes to 100, well its x20 then if we multiply 1 x 20 we'll get 20. So, he is correct, 1/5 = 20%. Remember what number we think of when we hear the word percent, the number is 100.
