How do you solve this system of equations using the addition method:
4
x
−
y
=
−
4
;
5
x
+
2
y
=
−
18
?
Algebra
1 Answer
IDKwhatName
Jun 30, 2017
x
=
−
2
,
y
=
−
4
Explanation:
Right now, you have:
4
x
−
y
=
−
4
5
x
+
2
y
=
−
18
To make this easier, you must get rid of one variable, in this case I will remove
y
, to do this you must make the y-values in both equations the same.
To do this, I will multiply the whole of
4
x
−
y
=
−
4
by 2 to give
8
x
−
2
y
=
−
8
We now have:
8
x
−
2
y
=
−
8
5
z
+
2
y
=
−
18
All we need to do now is
(
8
x
−
2
y
+
5
x
+
2
y
)
=
(
−
18
−
8
)
≡
13
x
=
−
26
.
Divide both sides by 13 to find
x
:
13
x
=
−
26
13
x
13
=
−
26
13
x
=
−
2
Now put your value for
x
into either equation:
4
(
−
2
)
−
y
=
−
4
−
8
−
y
=
−
4
y
=
−
8
+
4
y
=
−
4
x
=
−
2
;
y
=
−
4
Answer link
Answer:
jaxoscxhdnsidsbc
Step-by-step explanation:
aciowshavpaslkn oica xhkvsaih oilcs
6x +30 -3x +6 =12x +18
3x +36 =12x +18
3x-12x = 18 -36
-9x = -18 | -1
9x =18
x= 18/9
x=2
no, since a rectangle requires 90-degree corners, and every angle inside an equilateral triangle is 60-degrees. The only multiple of 90 that you can make is 180-degrees (or any multiple of it).
Answer:
|x-2| + |x+1| -5=0
⇒|x-2| + |x+1|=5
⇒x-2+x+1=5
⇒2x=6
⇒x=3
Step-by-step explanation:
