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kupik [55]
3 years ago
10

Why would a railway be important to either side in the civil war?

Mathematics
2 answers:
igomit [66]3 years ago
8 0
To transport food the wounded ammo and healthy tripp’s
GaryK [48]3 years ago
7 0

Answer:

Either side would have been improved by a railway so they could get more ammo in and get food in and also get the sick and wonded out to get medical attention

Step-by-step explanation:

You might be interested in
It takes Amy twice as long to deliver papers as it does Nancy. How long would it take each girl to deliver the papers by herself
ANEK [815]

Answer:

so if it takes twice all long for amy as nacy that means

Amy takes 2/3 or 0.6(aprox)

Nacy takes 1/3 or 0.3(aprox)

Amy=24

Nacy=12

Hope This Helps!!!

3 0
2 years ago
I’m thinking the answer should be B right ??
laiz [17]

Hello!

The formula for the volume of a sphere is \frac{4}{3} \pi r³.

Let's plug in our radius.

\frac{4}{3} \pi (1,000)

As we are not looking for an exact answer,we can look for an answer in terms of pi. Maybe we could multiply our fraction by 1,000.

\frac{4000}{3} \pi

Therefore, our answer is D.

I hope this helps!

7 0
3 years ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
Pls help me .question no 14
Alex_Xolod [135]

Question 14, Part (i)

Focus on quadrilateral ABCD. The interior angles add to 360 (this is true for any quadrilateral), so,

A+B+C+D = 360

A+90+C+90 = 360

A+C+180 = 360

A+C = 360-180

A+C = 180

Since angles A and C add to 180, this shows they are supplementary. This is the same as saying angles 2 and 3 are supplementary.

==================================================

Question 14, Part (ii)

Let

x = measure of angle 1

y = measure of angle 2

z = measure of angle 3

Back in part (i) above, we showed that y + z = 180

Note that angles 1 and 2 are adjacent to form a straight line, so we can say

x+y = 180

-------

We have the two equations x+y = 180 and y+z = 180 to form this system of equations

\begin{cases}x+y = 180\\y+z = 180\end{cases}

Which is really the same as this system

\begin{cases}x+y+0 = 180\\0+y+z = 180\end{cases}

The 0s help align the y terms up. Subtracting straight down leads to the equation x-z = 0 and we can solve to get x = z. Therefore showing that angle 1 and angle 3 are congruent. We could also use the substitution rule to end up with x = z as well.

4 0
3 years ago
Please help! solve for x!
olga55 [171]

Answer:

x = 9

-1 + 14x = 12x + 17

7 0
2 years ago
Read 2 more answers
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