Answer:
Required number is 4.
Step-by-step explanation:
Let the required number be a.
Given,
Sum of ten times the integer and seven times it’s square is 152.
= > Ten times of a + seven times of it's square = 152
= > 10( a ) + 7( a )^2 = 152
= > 10a + 7a^2 - 152 = 0
= > 7a^2 + 10a - 152 = 0
= > 7a^2 + ( 38 - 28 )a - 152 = 0
= > 7a^2 + 38a - 28a - 152 = 0
= > a( 7a + 38 ) - 4( 7a + 38 ) = 0
= > ( a - 4 )( 7a + 38 ) = 0
= > a = 4 or - 38 / 7
Hence the required number is 4.
Ax^2 + bx + c is a quadratic trinomial. Therefore, ur expression is a quadratic trinomial......it is a trinomial because it has 3 terms.....quadratic means the highest exponent is 2.
Answer:
10x-20
Step-by-step explanation:
(5×2x)-(5×4)
10x-20
Answer:
Step-by-step explanation:
x 0 , VCB ln(1 4x2 ) tương đương với
