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vladimir2022 [97]
2 years ago
7

I have a two digit number the sum of the digits is 12 the first digit is 4 Less Than 3 times the second what is my number​

Mathematics
1 answer:
nignag [31]2 years ago
3 0

Answer:

84

Step-by-step explanation:

Let the first digit = x

Let the second digit =y

x + y = 12

x + 4 = 3*y

===========

From the second equation, we learn that x = 3y - 4

Put that into the first equation.

3y - 4 + y = 12          Combine the left side

4y - 4 = 12                Add 4 to both sides

4y = 16                     Divide by 4

4y/4 = 16/4        

y = 4  

=================

x + 4 = 12

x + 4 - 4 = 12-4

x = 8

So the number is 84

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Answer:

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Step-by-step explanation:

then I can help u

6 0
2 years ago
Find the value of x (3/5)^x(5/3)^2x=125/27​
lesya692 [45]

Given:

The equation is

\left(\dfrac{3}{5}\right)^x\left(\dfrac{5}{3}\right)^{2x}=\dfrac{125}{27}

To find:

The value of x.

Solution:

We have,

\left(\dfrac{3}{5}\right)^x\left(\dfrac{5}{3}\right)^{2x}=\dfrac{125}{27}

\left(\dfrac{5}{3}\right)^{-x}\left(\dfrac{5}{3}\right)^{2x}=\dfrac{5\times 5\times 5}{3\times 3\times 3}      [\because \left(\dfrac{a}{b}\right)^{-m}=\left(\dfrac{b}{a}\right)^{m}]

\left(\dfrac{5}{3}\right)^{-x+2x}=\dfrac{5^3}{3^3}          [\because a^ma^n=a^{m+n}]

\left(\dfrac{5}{3}\right)^{x}=\left(\dfrac{5}{3}\right)^{3}

On comparing the exponents, we get

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8 0
2 years ago
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6 0
3 years ago
Marcus has three random samples of the same size from a population of 700 people. In one sample, 53% of people have a library ca
Lapatulllka [165]

Answer:

343

Step-by-step explanation:

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5 0
2 years ago
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