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Ksivusya [100]
4 years ago
7

ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions

.

Mathematics
2 answers:
Elan Coil [88]4 years ago
7 0

In the function given, it can take any x variable without it causing any problems in the function when solved.

So, any value can be x (all real numbers)

Best of Luck!

EastWind [94]4 years ago
5 0

Answer:

all real numbers

Step-by-step explanation:

The domain is the values that x can take

There are no restrictions as to what x can be in this function

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Scientists want to estimate the mean weight of mice after they have been fed a
krek1111 [17]

Answer:

n = 484

Step-by-step explanation:

If Confidence Interval  CI = 95 %   then α = 5%  and α/2 = 2,5 %

α/2 = 0,0125

MOE for normal distribution is:

MOE = z * σ/√n

For α/2 = 0,0125    ⇒ z(score) = -2,2

MOE = |-2,2| * 4/√n

0,4*√n = 8,8

√n = 8,8 / 0,4

√n = 22

n = 484

5 0
3 years ago
HELP PLEASE !!! Place each expression under the equivalent expression in the table.
tino4ka555 [31]

Answer:

Option 3,5 are under first expression and Option 1,2 are under second expression.

Step-by-step explanation:

1). \frac{(x-4)(x+2)}{x^{2}+5x+6}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{(x-4)(x+2)}{(x+3)(x+2)}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}=\frac{(x-4)}{(x+3)}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{(x-4)(4x-5)-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{4x^{2}-5x-16x+20-3x^{2}+24x-20}{(x+3)(4x-5)}=\frac{x^{2}+3x}{(x+3)(4x-5)}

=\frac{x(x+3)}{(x+3)(4x-5)}=\frac{x}{4x-5}

2). \frac{3x}{4x-5}-\frac{4x^{2}}{8x^{2}-10x}=\frac{3x}{4x-5}-\frac{4x}{8x-10}=\frac{3x(8x-10)-4x(4x-5)}{(4x-5)(8x-10)}

=\frac{24x^{2}-30x-16x^{2}+20x}{(4x-5)(8x-10)}

=\frac{8x^{2}-10x}{(4x-5)(8x-10)}=\frac{x(8x-10)}{(4x-5)(8x-10)}=\frac{x}{4x-5}

3). \frac{6x^{2}}{x^{2}-7x+10}\div \frac{2x}{x-5}

=\frac{6x^{2}}{x^{2}-7x+10}\times \frac{x-5}{2x}

=\frac{3x(x-5)}{x^{2}-7x+10}

=\frac{3x(x-5)}{(x-5)(x-2)}=\frac{3x}{x-2}

4). \frac{-x}{4x-5}-\frac{4x^{2}}{16x^{2}-22x}

=\frac{-x}{4x-5}-\frac{2x}{8x-11}

=\frac{-x(8x-11)-2x(4x-5)}{(4x-5)(8x-11)}

=\frac{-8x^{2}+11x-8x^{2}+10x}{(4x-5)(8x-11)}

=\frac{-16x^{2}+21x}{(4x-5)(8x-11)}=\frac{-x(16x-21)}{(4x-5)(8x-11)}

5). \frac{3x^{2}}{x+3}\times \frac{2(x+3)}{2x^{2}-4x}

=\frac{6x^{2}(x+3)}{2x(x+3)(x-2)}=\frac{3x}{x-2}

6). \frac{5x^{2}}{x-2}\times \frac{2x+6}{8x^{2}-4x}

=\frac{10x^{2}(x+3)}{4x(x-2)(2x-1)}

4 0
4 years ago
Read 2 more answers
Write the function for the following set of ordered pairs. (0,10), (3,25), (5,35), (10,60).
noname [10]
Hmm, so they seem to be increaeing by powers of 5
10=2 times 5
25=5 times 5
35=7 times 5
60=12 times 5

so maybe it is
nth term=5(n+2) or 5n+10
lets try it
0th term
5(0)+10
0+10=10
corrrect

3rd term
5(3)+10
15+10
25
correct



so the function is
f(x)=5(x+2)
5 0
3 years ago
Which values of a and b make the following equation true<br> (5x^7y^2) (-4x^4y^5) = -20x^a y^b
Nadya [2.5K]
In x^7•x^4, how many x’s are multiplied together? (There’s 7 in the first factor and 4 in the second.)

x^7•x^4 = x^__? This is your a-value.

Similarly, y^2•y^5 = y^__? How many y’s are there in total being multiplied? This is your b-value.
5 0
3 years ago
Evaluate the expression 2x - 5 when x =3?<br>A) -4<br>B) 1<br>C) 6<br>D) 11<br><br>​
asambeis [7]

Answer:

B)1

Step-by-step explanation:

When you replace x with three your equation is 2*3-5. By doing order of operations you multiply 2*3 and get 6 then subtract 5 getting 1.

5 0
4 years ago
Read 2 more answers
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