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seropon [69]
3 years ago
15

P is the incenter of QRS. Use the given information to determine find the indicated measure.

Mathematics
1 answer:
never [62]3 years ago
5 0
<span>The incenter is equidistant from all three triangle sides.
So, PJ = PK = PL.
PJ = 4x -8
PL = x + 7

Therefore,
</span>4x -8 = <span>x + 7
3x = 15
x = 5
So, PJ = 12
PL = 12 and
PK = 12

</span>
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A baseball team's total wins and losses for one season is 162. The number of wins is 6 less than 2 times the number of losses. W
aivan3 [116]

Answer:

x + y = 162 and x = 2y - 6

Step-by-step explanation:

Let the total wins be x

Let the total loss be y

If a baseball team's total wins and losses for one season is 162, this can be expressed as;

x + y = 162 ....... 1

If the number of wins is 6 less than 2 times the number of losses, this is expressed as;

2 times the number of losses = 2y

6 less than 2 times the number of losses = 2y - 6

Now, If the number of wins is 6 less than 2 times the number of losses this is expressed as;

x = 2y - 6 .... 2

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Read 2 more answers
What is the probability that a random person who tests positive for a certain blood disease actually has the disease, if we know
xeze [42]

Answer:

Step-by-step explanation:

Hello!

Any medical test used to detect certain sicknesses have several probabilities associated with their results.

Positive (test is +) ⇒ P(+)

True positive (test is + and the patient is sick) ⇒ P(+ ∩ S)

False-positive (test is + but the patient is healthy) ⇒P(+ ∩ H)

Negative (test is -) ⇒ P(-)

True negative (test is - and the patient is healthy) ⇒ P(- ∩ H)

False-negative (test is - but the patient is sick) ⇒ P(- ∩ S)

The sensibility of the test is defined as the capacity of the test to detect the sickness in sick patients (true  positive rate).

⇒ P(+/S) =<u> P(+ ∩ S)  </u>

                    P(S)

The specificity of the test is the capacity of the test to have a negative result when the patients are truly  healthy (true negative rate)

⇒ P(-/H) =<u> P(- ∩ H)  </u>

                   P(H)

For this particular blood disease the following probabilities are known:

1% of the population has the disease: P(S)= 0.01

95% of those who are sick, test positive for it: P(+/S)= 0.95 (sensibility of the test)

2% of those who don't have the disease, test positive for it: P(+/H)= 0.02

The probability of a person having the blood sickness given that the test was positive is:

P(S/+)= <u> P(+ ∩ S)  </u>

                P(+)

The first step you need to calculate the intersection between both events + and S, for that you will use the information about the sickness prevalence in the population and the sensibility of the test:

P(+/S) =<u> P(+ ∩ S) </u>

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P(+/S)* P(S)  = P(+ ∩ S)  

P(+ ∩ S) = 0.95*0.01= 0.0095

The second step is to calculate the probability of the test being positive:

P(+)=  P(+ ∩ S) +  P(+ ∩ H)

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Then you can clear the value of P(+ ∩ H):

P(+/H) =<u> P(+ ∩ H) </u>

                 P(H)

P(+/H)*P(H)  = P(+ ∩ H)

P(+ ∩ H) = 0.02*0.99= 0.0198

Next you can calculate P(+):

P(+)=  P(+ ∩ S) +  P(+ ∩ H)= 0.0095 + 0.0198= 0.0293

Now you can calculate the asked probability:

P(S/+)= <u> P(+ ∩ S)  </u> =<u> 0.0095 </u>= 0.32

                P(+)        0.0293

I hope it helps!

                 

                 

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