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professor190 [17]
3 years ago
6

Arnold’s entire workout consisted of 10 minutes of warm-up exercises, 25 minutes of lifting weights, and 15 minutes on the tread

mill. What was the ratio of the number of minutes he lifted weights to the total number of minutes of his entire workout?
Mathematics
2 answers:
lilavasa [31]3 years ago
8 0

Answer:

1 to 2

1:2

1/2

Step-by-step explanation:

Ratios can be written in three forms:

A to B

A:B

A/B

Ratios are also simplified by reducing to lowest terms like fractions are.

This problem's ratio is:

minutes lifted weights to total minutes workout

The number of minutes lifting weights is in the question: 25.

To find the total minutes of his workout, add the number of minutes he spent for all of the activities:

Total minutes = warm-up + lifting weights + treadmill

Total minutes = 10 + 25 + 15

Total minutes = 50

The ratio before simplifying is 25/50.

This ratio can be reduced to lowest terms. Both sides are divisible by 25.

25/25 = 1

50/25 = 2

The ratio in lowest terms is 1/2.

It can also be written as 1 to 2 or 1:2.

Sergeeva-Olga [200]3 years ago
6 0

Answer:

1:2

Step-by-step explanation:

Find the ratio of the ratio of the number of minutes he lifted weights to the total number of minutes of his entire workout and simplify it

25:10+25+15

25:50

1:2

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in 2006 ,the enrollment at jefferson high school was 1,200 students in 2012 the enrollment at jefferson high school was 1,650 st
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Three Texas drovers met on a highway and began to dicker as follows:
Alik [6]

Answer:

  • Jim's: 7
  • Duke's: 21
  • Hank's: 11

Step-by-step explanation:

Let J, D, and H represent the drove sizes of Jim, Duke, and Hank.

  2(H -6 + 1) = (J +6 -1) . . . . . Hank's offer

  3(D -14 +1) = (H +14 -1) . . . . Duke's offer

  6(J -4 +1) = (D +4 -1) . . . . . . Jim's offer

These equations can be simplified to ...

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  3D - H = 52

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__

<u>Solution</u>

Adding twice the second equation to the first gives ...

  2(3D -H) +(2H -J) = 2(52) +(15)

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Adding 6 times the third equation to this one gives ...

  6(6J -D) +(6D -J) = 6(21) +(119)

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Using this value in the third equation gives ...

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Using the value of J in the first equation gives ...

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Then the solution is (J, D, H) = (7, 21, 11).

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5 0
3 years ago
The domain of the following relation: R {(6, -2), (1, 2), (-3, -4), (-3, 2)} is
monitta
The domain is the set of possible inputs, i.e. the x-coordinates of the points.

Here those are 6, 1 and - 3 which in order is -3, 1, 6.

Then the answer is {-3, 1, 6}.

By the way note that this relation is not a function. Do you know why?

Because the image of -3 is not stated unambiguosly.



5 0
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