Answer:
O.1M
Explanation:
First let's generate a balanced equation for the reaction
NaOH + HCl —>NaCl + H2O
From the equation,
The ratio of the acid to base is 1:1.
From the question, we obtained the following:
Ma = Molarity of acid = 0.12M
Va = volume of acid = 21.35cm3
Vb = volume of base = 25.55cm3
Mb = Molarity of base =?
We obtained nA(mole of acid) and nB(mole of base) to be 1
The molarity of the base can be calculated for using:
MaVa/ MbVb = nA / nB
0.12x21.35 / Mb x 25.55 = 1
Cross multiply to express in linear form
Mb x 25.55 = 0.12x21.35
Divide both side by 25.55
Mb = (0.12x21.35) / 25.55
Mb = 0.1M
The molarity of the base is 0.1M
Answer:
80.1 = 6158.46
Multiply 9.119.11 by 1010.
91.1−11=6.02⋅102391.1-11=6.02⋅1023
Subtract 1111 from 91.191.1.
80.1=6.02⋅102380.1=6.02⋅1023
Multiply 6.026.02 by 10231023.
80.1=6158.4
Answer:
40 C atoms
Explanation:
Step 1: Write organic compound
10C₄H₁₀
We see here that in 1 mol of C₄H₁₀, we would have 4 atoms of C.
We are given that we have 10 moles of C₄H₁₀.
Therefore, we have 4 · 10 = 40 atoms C
The paper in the straw makes the soda fizz.
<h2><u>
PLEASE MARK BRAINLIEST!</u></h2>
In Step 5, you will calculate H+/OH– ratios for more extreme pH solutions. Find the concentration of H+ ions to OH– ions listed in Table B of your Student Guide for a solution at a pH = 2. Then divide the H+ concentration by the OH– concentration. Record these concentrations and ratio in Table C.
What is the concentration of H+ ions at a pH = 2?
<h3>
0.01 mol/L </h3>
What is the concentration of OH– ions at a pH = 2?
<h3>
0.000000000001 mol/L
</h3>
What is the ratio of H+ ions to OH– ions at a pH = 2?
<h3>
10,000,000,000 : 1</h3>
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Those are your correct answers on edg2020!
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<em>I hope this helps!</em>