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lubasha [3.4K]
2 years ago
6

Which ions aren't shown in net ionic reactions, because they are present as both reactants and products of the reaction, so they

do not participate in the reaction?
Chemistry
1 answer:
Anvisha [2.4K]2 years ago
7 0

Explanation:

This is correct!

Ions that exist in both the reactant and product side of the equation are referred to as spectator ions. Overall, they do not partake in the reaction. If they are present on both sides of the equation, you can cancel them out.

An example is;

Na+(aq) + Cl​−​​(aq) + Ag​+(aq) + NO​3​−​​(aq) → Na​+​​(aq) + NO​3​−​​(aq) + AgCl(s)

The ions; Na+, NO​3​−​​(aq) would be cancelled out to give;

Cl​−​​(aq) + Ag​+(aq)  → AgCl(s)

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How do you use nonmetal in a sentence?
skad [1K]
Here Is A Sentence You Could Possibly Use:

"Hydrogen and Nitrogen are two examples of non-metals."

(You can replace the two given elements with whatever two non-metallic elements you like.)

Hope This Helps!

BTW, You May Want A Second Opinion Just In Case! :)
7 0
3 years ago
Five kg of carbon dioxide (CO2) gas undergoes a process in a well-insulated piston-cylinder assembly from 2 bar, 280 K to 20 bar
kaheart [24]

This question is incomplete, the complete question is;

Five kg of carbon dioxide (CO2) gas undergoes a process in a well-insulated piston-cylinder assembly from 2 bar, 280 K to 20 bar, 520 K. If the carbon dioxide behaves as an ideal gas, determine the amount of entropy produced, in kJ/K. Assuming;

a) constant specific heats Cp = 0.939 kJ/Kg K

b) variable specific heats

Answer:

a) the amount of entropy produced is 0.731599 kJ/K

b) the amount of entropy produced is 0.69845 kJ/K

Explanation:

Given the data in the question;

5 kg of carbon dioxide (CO₂) gas undergoes a process in a well-insulated piston-cylinder assembly.

m = 5 kg

Molar mass M = 44.01 g/mol

P₁ = 2 bar, P₂ = 20

T₁ = 280 K, P₂ = 520 K

Since its insulated { q = 0 } ( kinetic and potential energy effects = 0 )

Now,

a) the amount of entropy produced, in kJ/K, Assuming constant specific heats with Cp = 0.939 kJ/Kg K

S_{Generation = m × ((Cp × In( T₂/T₁) - R × In( P₂/p₁ ))

we substitute

S_{Generation = 5 × (( 0.939  × In( 520/280) - 0.1889 × In( 20/2 ))

= 5 × ( 0.5812778 - 0.434958 )

= 5 × 0.1463198

= 0.731599 kJ/K

Therefore, the amount of entropy produced is 0.731599 kJ/K

b) the amount of entropy produced, in kJ/K, Assuming variable specific heats.

Now, from  Table A-23: Ideal Gas Properties of Selected Gases;

T₁,T₂ : s₁⁰ = 211.376 kJ/kmol-K, s₂⁰ = 236.575 kJ/kmol-K

now, s₁ = s₁⁰ / M and s₂ = s₂⁰ / M

we substitute

s₁ = s₁⁰ / M = 211.376 / 44.01  = 4.8029 kJ/kg

s₂ = s₂⁰ / M = 236.575 / 44.01 = 5.37548 kJ/kg

S_{Generation = m × (( s₂ - s₁ ) - R × In( p₂ / p₁ ))

we substitute

S_{Generation = 5 × (( 5.37548 - 4.8029  ) - 0.1880 × In( 20 / 2 ))

= 5 × ( 0.57258 - 0.432885997 )

= 5 × 0.13969

= 0.69845 kJ/K

Therefore, the amount of entropy produced is 0.69845 kJ/K

5 0
2 years ago
NASA communicates with the Space Shuttle and International Space Station using Ku-band microwave radio. Suppose NASA transmits a
Margarita [4]

Answer:

λ = 0.0167 m = 16.7 mm

Explanation:

The wavelength of these radio waves can be found out by using the formula for the speed of radio waves:

v = fλ

where,

v = speed of radio waves = speed of light = 3 x 10⁸ m/s

f = frequency of radio waves = 18 GHz = 18 x 10⁹ Hz

λ = Wavelength = ?

Therefore,

3 x 10⁸ m/s = (18 x 10⁹ Hz)λ

λ = (3 x 10⁸ m/s)/(18 x 10⁹ Hz)

<u>λ = 0.0167 m = 16.7 mm</u>

4 0
2 years ago
A mixture of 10 cm3 of methane and 10 cm3 of ethane was sparked with an excess of oxygen. After cooling to room temperature, thr
Tpy6a [65]
In the combustion process using excess oxygen, each mole of methane results to 1 mole of co2 while ethane produces 2 moles of Co2. Under same conditions, these can be translated to volume. Hence the total volume absorbed is 10 cm3 + 20 cm3 = 30 cm3.
5 0
2 years ago
What is the hyphen notation of nitrogen
vovikov84 [41]
<span> N-16

</span>7 protons & 9 neutrons
<span>7 + 9 = 16

</span>
6 0
3 years ago
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