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lubasha [3.4K]
3 years ago
6

Which ions aren't shown in net ionic reactions, because they are present as both reactants and products of the reaction, so they

do not participate in the reaction?
Chemistry
1 answer:
Anvisha [2.4K]3 years ago
7 0

Explanation:

This is correct!

Ions that exist in both the reactant and product side of the equation are referred to as spectator ions. Overall, they do not partake in the reaction. If they are present on both sides of the equation, you can cancel them out.

An example is;

Na+(aq) + Cl​−​​(aq) + Ag​+(aq) + NO​3​−​​(aq) → Na​+​​(aq) + NO​3​−​​(aq) + AgCl(s)

The ions; Na+, NO​3​−​​(aq) would be cancelled out to give;

Cl​−​​(aq) + Ag​+(aq)  → AgCl(s)

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A. Gallium is produced by the electrolysis of a solution obtained by dissolving gallium oxide in concentrated NaOH(aq). Calculat
liraira [26]

Answer:

A)Mass of  gallium plated out is 0.3440 grams

B) For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.

Explanation:

To calculate the total charge, we use the equation:

C=I\times t

where,

C = Charge

I = Current in time t (seconds)

To calculate the moles of electrons, we use the equation:

\text{Moles of electrons}=\frac{C}{F}

where,

F = Faraday's constant = 96500

A) The equation for the deposition of Ga(s) from Ga(III) solution follows:

Ga^{3+}(aq.)+3e^-\rightarrow Ga(s)

I = 0.790 A, t = 30.0 min = 1800 seconds

C=I\times t

C=0.790 A\times 1800 s=1422 C

Moles of electron transferred:

=\frac{1422 C}{96500 F}=0.01474 mol

Now, to calculate the moles of gallium, we use the equation:

\text{Moles of Gallium}=\frac{\text{Moles of electrons}}{n}

n = number of electrons transferred = 3

\text{Moles of Gallium}=\frac{0.01474 mol}{3}=0.004913 mol

Mass of 0.004913 moles of gallium = 0.004913 mol × 70 g/mol=0.3440 g

B) The equation for the deposition of Sn(s) from Sn(II) solution follows:

Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)

Moles of tin = \frac{8.70 g}{119 g/mol}=0.07311 mol

n = number of electrons transferred = 2

\text{Moles of tin}=\frac{\text{Moles of electrons}}{n}

Moles of electron =  n\times \text{Moles of tin}

=2\times 0.07311 mol=0.14622 mol

Charge transferred during time t :

\text{Moles of electrons}=\frac{C}{F}

C=96500 F\times 0.14622 mol=14,110.23 C

Current applied for t time = I = 5.79 A

t=\frac{C}{I}=\frac{14,110.23 C}{5.79 A}=2,437 s=0.67 hrs

For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.

5 0
4 years ago
Define physical and chemical properties, provide three examples of each, discuss their reversibility, and explain the fundamenta
Anton [14]

Answer:

Physical properties are defined as the properties which can be observed without changing its chemical composition.

Explanation:

5 0
3 years ago
For an electron with angular (azimuthal) quantum number ℓ = 2, the magnetic quantum number m can have
Paraphin [41]

Answer:

-2, -1, 0, +1, +2

Explanation:

The quantum numbers describe the quantum state of an electron in an atom. These numbers are symbolized as n, l, m, and s. There are rules for the combination of these numbers. The angular quantum number (ℓ) is related to the magnetic number (<em>m</em>): if ℓ is equal to a number a, thus <em>m</em> can be any integer number between - a and +a.

According to this rule:

If ℓ = 2, thus <em>m</em> can be have a value of an integer between -2 and +2 ⇒ -2, -1, 0, +1, +2

6 0
3 years ago
Describe the composition of the nucleus of an atom.
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the answer is b it is composed of protons and neutrons.

hope this helped

3 0
3 years ago
Duncan knows that it takes 36400 cal of energy to heat a pint of water from room temperature to boiling. However, Duncan has pre
brilliants [131]

Answer:

\large \boxed{\text{122 000 J}}

Explanation:

1. Calculate the energy needed

\text{Energy} = \text{0.800 pt} \times \dfrac{\text{36 400 cal}}{\text{1 pt}}  = \text{ 29 120 cal}

2. Convert calories to joules

\text{Energy} = \text{29 120 cal} \times \dfrac{\text{4.184 J}}{\text{1 cal}} = \textbf{122 000 J}\\\\\text{The water will have absorbed $\large \boxed{\textbf{122 000 J}}$}

8 0
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