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lubasha [3.4K]
2 years ago
6

Which ions aren't shown in net ionic reactions, because they are present as both reactants and products of the reaction, so they

do not participate in the reaction?
Chemistry
1 answer:
Anvisha [2.4K]2 years ago
7 0

Explanation:

This is correct!

Ions that exist in both the reactant and product side of the equation are referred to as spectator ions. Overall, they do not partake in the reaction. If they are present on both sides of the equation, you can cancel them out.

An example is;

Na+(aq) + Cl​−​​(aq) + Ag​+(aq) + NO​3​−​​(aq) → Na​+​​(aq) + NO​3​−​​(aq) + AgCl(s)

The ions; Na+, NO​3​−​​(aq) would be cancelled out to give;

Cl​−​​(aq) + Ag​+(aq)  → AgCl(s)

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What is it called when an enzyme changes shape
7nadin3 [17]

Answer: Induced Fit

Explanation: The process wherein the enzymes change their shape is called as induced fit. It is the precision aligning of enzymes essential for catalytic activity which is caused by the binding of the substrate as enzymes possess active sites. Hence, as the substrate approaches the enzymes, the enzyme alters its shape.

4 0
1 year ago
Write the balanced molecular, ionic, and net ionic equations for the reaction when a solution of lithium phosphate is mixed with
Kaylis [27]

Answer:

see explaination

Explanation:

Molecular equation;

2Li3PO4(aq) + 3CaCl2(aq) >>>> Ca3(PO4)2(s) + 6LiCl(aq)

Total ionic equation; . Includes all ions ;

6Li^+(aq) + 2PO4^-3(aq) + 3Ca^+2(aq) + 6Cl^-(aq) >>>> Ca3(PO4)2(s) + 6Li^+(aq) + 6Cl^-(aq)

Net ionic equation; remove common ions from total ionic;

2PO4^-3(aq) + 3Ca^+2(aq) >>>> Ca3(PO4)2(s)

6 0
3 years ago
Typical "hard" water contains about 2.0 x 10–3 mol of Ca2+ per liter. Calculate the maximum concentration of fluoride ion that c
malfutka [58]

Answer:

[F^-]_{max}=4x10{-3}\frac{molF^-}{L}

Explanation:

Hello,

In this case, for the described situation, we infer that calcium reacts with fluoride ions to yield insoluble calcium fluoride as shown below:

Ca^{+2}(aq)+2F^-(aq)\rightleftharpoons CaF_2(s)

Which is typically an equilibrium reaction, since calcium fluoride is able to come back to the ions. In such a way, since the maximum amount is computed via stoichiometry, we can see a 1:2 mole ratio between the ions, therefore, the required maximum amount of fluoride ions in the "hard" water (assuming no other ions) turns out:

[F^-]_{max}=2.0x10^{-3}\frac{molCa^{2+}}{L}*\frac{2molF^-}{1molCa^{2+}}  \\

[F^-]_{max}=4x10{-3}\frac{molF^-}{L}

Best regards.

8 0
3 years ago
You need to make 10 mL of 2 mg/ml solution of protein and you have 25 mg/mL solution. How much protein solution and water do you
meriva

Answer:

0.8 mL of protein solution, 9.2 mL of water

Explanation:

The dilution equation can be used to relate the concentration C₁ and volume V₁ of the stock/undiluted solution to the concentration C₂ and volume V₂ of the diluted solution:

C₁V₁ = C₂V₂

We would like to calculate the value for V₁, the volume of the inital solution that we need to dilute to make the required solution.

V₁ = (C₂V₂) / C₁ = (2mg/mL x 10mL) / (25 mg/mL) = 0.8 mL

Thus, a volume of 0.8 mL of protein solution should be diluted with enough water to bring the total volume to 10 mL. The amount of water needed is:

(10 mL - 0.8 mL) = 9.2 mL

6 0
2 years ago
Why cant (NaCl) light the bulb until the NaCl is dissolved in water. *
Aneli [31]

Answer:

NaCl will only conduct electricity in solutions

Explanation:

For electrical conduction, free mobile electrons as seen in most metals must be present or ions which are charged particles must be available for solutions and molten substances.

  • Sodium chloride is an ionic compound without free mobile electrons or ions despite being ionic.
  • It will maintain a subtle and unique charge stability when in solid form.
  • In solid, the ions are not free to move and remain locked up in the solid mass.
  • When introduced into a solution, the ions becomes free to move and this will aid electrical conduction.
6 0
3 years ago
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