Answer:
Amount of heat energy released by light bulb = 25 joules
Explanation:
Given:
Energy receive by light bulb = 100 Joules
Energy released by light bulb as light energy = 75 Joules
Find:
Amount of heat energy released by light bulb
Computation:
We know that, energy is neither be created nor destroys
So,
Using Law of conservation of energy
Energy receive by light bulb = Energy released by light bulb as light energy + Amount of heat energy released by light bulb
100 = 75 + Amount of heat energy released by light bulb
Amount of heat energy released by light bulb = 100 - 75
Amount of heat energy released by light bulb = 25 joules
so you can see those fluorine atoms have really spread out around the central phosphorus atom. this gives us a trigonal bi-pyramidal molecular geometry for pf5.
Answer:
hope this helps :)
Explanation:
for the first one, you can look at the periodic table and look at the atomic number and it will show you how many protons there are giving you the answer because protons and electrons are equal in a pure element
a- carbon
b- neon
c- boron
d- oxygen
e- helium
f- hydrogen
g- lithium
h- beryllium
i- nitrogen
1- sulfur
2- S
3- 16
4- 32.066
5- 16
6- 16
7- 16.066
8- draw circles and put 16 dots like on the other page and in the middle put 16 nuetrons and electrons
9- 6 i think
D. due to the the water it will bring sand with the water there for us is D.
