State two substances that can be used as a filter in water treatment.

Calculate the ph of the solution upon the addition of 0.015 mol of naoh to the original buffer. express the ph to two decimal pl

tatiyna

You missed a lot of details in your question, so when we have the complete question as the attached picture so, the answer would be:

when we have the value of Ka = 1.8 x 10^-5 so, we can use it to get the Pka value

by using this formula:

Pka = -㏒Ka

= -㏒(1.8 x 10^-5)

= 4.7

now, after we have got the Pka we need now to get moles of NaC2H3O2 and

moles of HC2H3O2:

when moles of NaOH = 0.015 moles

when moles NaC2H3O2 after adding NaOH

= initial mol NaC2H3O2 + mol NaOH
∴moles NaC2H3O2 = 0.1 + 0.015 = 0.115 moles

and moles HC2H3O2 after adding NaOH

= initial mol HC2H3O2 - mol NaOH

∴ moles HC2H3O2 = 0.1 - 0.015 = 0.085 moles

so, when we have moles [HC2H3O2] &[NaC2H3O2] so we can substitution its values in [A] &[HA] :

by using H-H equation we can get the PH:

when PH = Pka + ㏒[A]/[HA]

PH = 4.7 + ㏒0.115/0.085

= 4.8

4 0

3 years ago

What current (in a) is required to plate out 2. 96 g of nickel from a solution of ni2 in 27. 12 minutes?

amid [387]

The current required to plate out 2.96 g of nickel from the solution of Ni²⁺ in 27.12 minutes is 5.95 A

<h3>Balanced equation </h3>

We'll begin by writing the balanced equation showing the number of faraday required to plate nickel. This is given below

Ni²⁺ + 2e —> Ni

Molar mass of Ni = 59 g/mol

Mass of Ni from the balanced equation = 1 × 59 = 59 g

Number of faraday = 2 F

1 faraday = 96500 C

2 faraday = 2 × 96500 = 193000 C

SUMMARY

From the balanced equation above,

59 g of Nickel was deposited by 193000 C of electricity

<h3>How to determine the quantity of electricity </h3>

From the balanced equation above,

59 g of Nickel was deposited by 193000 C of electricity

Therefore,

2.96 g of Nickel will be deposited by = (2.96 × 193000) / 59 = 9682.71 C of electricity

<h3>How to determine the current </h3>

Quantity of electricity (Q) = 9682.71 C
Time (t) = 27.12 mins = 27.12 × 60 = 1627.2 s
Current (I) =?

I = Q / t

I = 9682.71 / 1627.2

I = 5.95 A

Learn more about Faraday's law:

brainly.com/question/24795850

6 0

2 years ago

Read 2 more answers

Convert 100mL to L. Show your work to receive full credit.

Ilya [14]

Answer:

100 ml = 0.1 L

I divided 100 by 1000 because 1000ml = 1L

3 0

3 years ago

The 2 forces that act on atoms are the electromagnetic force and the strong nuclear force.

dolphi86 [110]

Electromagnetic forces occur between electrons and protons while nuclear forces occur between neutrons and protons in the nucleus.

Electromagnetic forces are the forces that are responsible for the attraction between electrons and protons. The electrons in shells repel each other.

The existence of electromagnetic forces explain why positively charged protons repel each other in the nucleus and neutrons are needed to buffer this effect.

The electromagnetic force has a short range. The strong nuclear force applies to the nucleus and focuses on the neutron - proton ratio.

An atom is unstable if it has too many protons because their repulsive force will exceed the nuclear force that keeps them together. Nuclear force is stronger for lighter nuclei than heavier ones.

Learn more: brainly.com/question/14396802

5 0

3 years ago

In the PhET simulation window, click the radio button labeled Mystery in the Blocks menu on the right-hand side of the screen. U

Yuliya22 [10]

Answer:

B, D, E, C, A

Explanation:

We have 5 blocks with their respective masses and volumes.

Block Mass Volume

A 65.14 kg 103.38 L

B 0.64 kg 100.64 L

C 4.08 kg 104.08 L

D 3.10 kg 103.10 L

E 3.53 kg 101.00 L

The density (ρ) is an intensive property resulting from dividing the mass (m) by the volume (V), that is, ρ = m / V

ρA = 65.14 kg / 103.38 L = 0.6301 kg/L

ρB = 0.64 kg / 100.64 L = 0.0064 kg/L

ρC = 4.08 kg / 104.08 L = 0.0392 kg/L

ρD = 3.10 kg / 103.10 L = 0.0301 kg/L

ρE = 3.53 kg / 101.00 L = 0.0350 kg/L

The order from least dense to most dense is B, D, E, C, A

4 0

3 years ago

State two substances that can be used as a filter in water treatment.​

State two substances that can be used as a filter in water treatment.