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3 years ago

10

A photo with a length of 4 inches and a width of 6 inches is enlarged to fit in a large picture frame. The photo and the enlarge

d picture are similar. The length of the enlarged picture is 14 inches. What is the width of the enlarged picture

1 answer:

Ivenika [448]3 years ago

8 0

Answer:

21 inches

Step-by-step explanation:

to get from 4 to 14 you multiply by 3.5 so you multiply 6 by 3.5 to get 21

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2 years ago

Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m

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The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

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Where, we have

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h- their eye-level height in feet

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$d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)$

For Addison h=85(1/3)

$d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)$

Subtracting both distances we get

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Therefore, the addison see to the horizon at 2 root 2mi.

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