Using implicit differentiation, it is found that the height of the pile is changing at a rate of 0.1415 feet per minute when the pile is 2 feet high.
The height of the pile is changing at a rate of 0.1415 feet per minute when the pile is 2 feet high.
Answer:
Time t = 1.39 seconds
Step-by-step explanation:
Given;
Initial velocity v = 20 ft/sec
height equation;
h = -16t^2 + 20t + 6
How long does it take for the disc to be caught 3 feet off the ground;
At this point h = 3
Substituting h = 3 into the height equation;
3 = -16t^2 + 20t + 6
-16t^2 + 20t + 6 - 3 = 0
-16t^2 + 20t + 3 = 0
Solving the quadratic equation;
t = 1.39 or t = -0.14
Since t cannot be negative;
Time t = 1.39 seconds
Because there is only one solution to this system, this means that the system is consistent and it is independent
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consistent = system has at least one solution
independent = each equation isn't reliant on the other; i.e. one equation doesn't completely overlap the other
Combine the two terms and they help describe any case where two lines cross at exactly one point. These two lines will have different slopes.
Answer:
Mass of the lamina is 24
Centre of Mass is ![(\frac{3}{4},\frac{3}{2})](https://tex.z-dn.net/?f=%28%5Cfrac%7B3%7D%7B4%7D%2C%5Cfrac%7B3%7D%7B2%7D%29)
Step-by-step explanation:
(1) the x-bound are 0≤x≤2
the line passing through (0,0) and (2,1) has equation y = x/2
line passing through (0,3) and (2,1) has equation y = -x + 3
so, the y-bound are x/2≤y≤-x +3
Check attachment for further calculations.....