Answer:
D
Step-by-step explanation:
D is 2x bigger than A, therefore is a scaled copy.
Answer:
268.0 in²
Step-by-step explanation:
refer to attached graphic as reference
volume of cone, V = (1/3) πr²h
in our case, we are given r = 4" and h = 16"
substituting this into equation:
V = (1/3) πr²h
= (1/3) ·(3.14) · (4)²· (16)
= 267.94667 in²
= 268.0 in² (nearest tenth)
Let
x = number of apples.
y = number of oranges.
we have to write the following equation to represent the problem:
4x + 6y = 15
To satisfy the equation, Jon must have used
x = 2.25
y = 1
Substituting
4 (2.25) +6 (1) = 15
9 + 6 = 15
answer
Jhon used 2.25kg of apple and 1kg of orange to make the salad.
Note: Since the problem does not have any other restrictions, there may be several apple and orange combinations that cost $ 15 per salad.
Hey there,
Length = 4x
Width = 3x
Perimeter = 112 inches
4x + 3x + 4x + 3x = 112 inches
14x = 112 inches
x = 112 inches / 14
= 8 inches
Length = 8 inches x 4
= 32 inches
Width = 8 inches x 3
= 24 inches
Hope this helps :))
<em>~Top♥</em>
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.