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Anastasy [175]
2 years ago
11

Question 4 help please

Mathematics
2 answers:
IgorC [24]2 years ago
6 0
I would say about 40%
denis23 [38]2 years ago
3 0
I agree 40% sounds right
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Please help!!! This is 12 points!!! I’ll mark brainliest!!!!
Nady [450]

Answer:

x: 23

y: -46

Step-by-step explanation:

so sorry if this is wrong, but i think thats it

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3 years ago
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Answer: 5-2.1= 2.9

5-2.17= 2.83

5-2 7/8= 2.125

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A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len
Gnom [1K]

Answer:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

df=n-1=93-1=92  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

\bar X=5.97 represent the sample mean for the length

s=0.4 represent the sample standard deviation

n=93 sample size  

\mu_o =6 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:  

Null hypothesis:\mu = 6  

Alternative hypothesis:\mu \neq 6  

since we don't know the population deviation the statistic is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing in formula (1) we got:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

P value

The degrees of freedom are given by:

df=n-1=93-1=92  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

5 0
2 years ago
Use the table to write a quadratic function in vertex form. Then rewrite the function in standard form.
Kisachek [45]

Answer:

Step-by-step explanation:

The graph decreases at first, then changes direction at (2, 5).

y = a(x-2)^2 + 5

Plug in (1,11) and solve for a:

11 = a(1-2)^2 + 5

a = 6

Equation in vertex form:

y = 6(x-2)^2 + 5

8 0
2 years ago
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