Answer:
80π
Step-by-step explanation:
Circle O with radius IO:
large radius = IO = 12 = R
Circle O with diameter JK
IJ = JK = KL = 2 × IO = 24
IJ = JK = KL = 24/3 = 8
small radius = 8/2 = 4 = r
The shaded area is a semicircle of radius 12 minus a semicircle of radius 4 plus two semicircles of radius 4.
That is the same as
1 semicircle of radius 12 plus 1 semicircle of radius 4
A = πR²/2 + πr²/2
A = π(12² + 4²)/2
A = 160π/2
A = 80π
Square root of 27 is the answer
Answer:
45 square meters
Step-by-step explanation:
we know that
The area of trapezoid is equal to
where
b1 and b2 are the parallel bases
h is the height of trapezoid (perpendicular distance between the parallel bases)
we have
substitute
12 divided by 3 is 4. the answer would be 40 as 4x10 is equal to 40
The answer is d 100 tan 40 degrees
