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3 years ago

8

free points Aiku has one piece of rope that is 45 centimeters long and another that is 367 centimeters long. How many meters of

rope does Aiku have in all? A.0.0412 m B.0.412 m C.4.12 m D.41.2 m

1 answer:

EleoNora [17]3 years ago

8 0

Answer:

4.12

Step-by-step explanation:

going from cm to m, divide length value by 100

45+367=412

412/100=4.12

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Step-by-step explanation:

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Let the event that a cell is killed be 'A' and the event where the ith nanotubule kill the cell be ' $\text{B}_i$ '.

This means that the cell will get killed if $\text{B}_1 \bigcup \text{B}_2 \bigcup \text{B}_3 \bigcup \text{B}_4 \bigcup \text{B}_5$ happens. This represents that the cell is killed if nanotubule 1 kills the cell, or nanotubule 2 kills the cell, and so on.

Here, P( $\text{B}_1$ ) = 0.2, P( $\text{B}_2$ ) = 0.4, P( $\text{B}_3$ ) = 0.3, P( $\text{B}_4$ ) = 0.6, P( $\text{B}_5$ ) = 0.5.

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P(A)= $1 - [(1 - P(\text{B}_1)) \times (1 - P(\text{B}_2)) \times (1 - P(\text{B}_3)) \times (1 - P(\text{B}_4)) \times (1 - P(\text{B}_5))]$

P(A) = $1 - [(1 - 0.2) \times (1 - 0.4) \times (1 - 0.3) \times (1 - 0.6) \times (1 - 0.5)]$

P(A) = $1 - (0.8 \times 0.6 \times 0.7 \times 0.4 \times 0.5)$

P(A) = 1 - 0.0672 = 0.9328

Hence, the probability that the cell will be killed is 0.9328.

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