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Mama L [17]
3 years ago
6

Factorization of Trinomial of x2^ - 8x - 48

Mathematics
1 answer:
cricket20 [7]3 years ago
7 0
12 and -4 or (x-12) (x+4)
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Evaluate for x = 3 and y = 4: x^-2y^2/x^0y^3 1/36 4/9 1024/9
GrogVix [38]

Answer:

\frac{1}{36}

Step-by-step explanation:

Evaluating the numerator and denominator before evaluating

Using the rule of exponents

a^{-n} ⇔ \frac{1}{a^{n} }, a^{0} = 1

Thus

x^{-2}y² ← substitute values into expression

= 3^{-2} × 4² = \frac{1}{9} × 16 = \frac{16}{9}

and denominator

x^{0}y^{3} = 1 × 4³ = 1 × 64 = 64

Now dividing

\frac{16}{9} ÷ 64

= \frac{16}{9} × \frac{1}{64} ( cancel 16 and 64 )

= \frac{1}{9(4)} = \frac{1}{36}

4 0
2 years ago
A volleyball reaches its maximum height of 13 feet, 3 seconds after its served. Which of the following quadratics could model th
julsineya [31]
Only selections B and D give a maximum height of 13 at t=3. However, both of those functions have the height be -5 at t=0, meaning the ball was served from 5 ft below ground. This does not seem like an appropriate model.

We suspect ...
• the "correct" answers are probably B and D
• whoever wrote the problem wasn't paying attention.

8 0
3 years ago
Read 2 more answers
Mike, Luke, and Alex each own a white hat marked with the first letter of their name. Winter owns a plain red hat, which is not
Karo-lina-s [1.5K]

Answer:switch mikes Luke’s and Alex in between each other and let winter keep her own

Step-by-step explanation:

7 0
2 years ago
Consider the equation 1.5 x plus 4.5 y equals 18.
Otrada [13]
1.5x will be the very answer
6 0
2 years ago
The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 mil
devlian [24]

Answer:

69.14% probability that the diameter of a selected bearing is greater than 84 millimeters

Step-by-step explanation:

According to the Question,

Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.

  • In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ

we have μ=87 , σ=6 & X=84

  • Find the probability that the diameter of a selected bearing is greater than 84 millimeters

This is 1 subtracted by the p-value of Z when X = 84.

So, Z = (84-87)/6

Z = -3/6

Z = -0.5 has a p-value of 0.30854.

⇒1 - 0.30854 = 0.69146

  • 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.

Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)

7 0
3 years ago
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