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ELEN [110]
3 years ago
13

How do I do this what is it asking

Mathematics
1 answer:
padilas [110]3 years ago
3 0
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

now.. notice the template above

so hmm  \bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

on a)  D is 2
on b)  D is -2
on c) A is 2
on d) A is 1/2


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Which of the relations given by the following sets of ordered pairs is not a function?
-Dominant- [34]

Answer:

Hi, there your answer will be C.

Step-by-step explanation:

The reason why is because X(Input) can not be repeated the same

for example the coordiante( 1,3) and (1,4). See there are two ones which make them not function

Also, if you're having trouble with Functions and nonfunctions

REMEMBER THS

Function: X and y has to be separarte  and can't have the same X

NON-FUNCTION- WHEN X REPEATS ITSELF

Hope this helps :)

7 0
3 years ago
Solve log 4x + log 13 = 0. Round to the nearest thousandth if necessary. a.0.019 b. 52 c.3.25 d. 0.311 Mathematics
kumpel [21]
Log4 + logX + log13 = 0
logX = -log13 - log4
logX = -1.716
x= 10^[-1.716]
x= 0.019 A
6 0
3 years ago
31.8 miles/hr= ? Feet/sec
PSYCHO15rus [73]
1 mi = 5280 ft
1 h = 3600 s

therefore:

31.8\ \dfrac{mi}{h}=31.8\cdot\dfrac{5280}{3600}\ \dfrac{ft}{s}=46.64\ \dfrac{ft}{s}

Answer: 31.8 mi/h = 46.64 ft/s
6 0
3 years ago
10) Choose the solution for each linear system.
hodyreva [135]

Answer:

<h2>10.  C. (2, -1)</h2><h2>11.  B. (-2, -4)</h2>

Step-by-step explanation:

10.

\left \{ {{x-2y=4} \atop {4x+2y+6}} \right.

The y values cancel out if you add the equations

5x = 10

x = 2

plug in x

2 - 2y = 4

-2y = 2

y=-1

Answer: C. (2, -1)

11.

\left \{ {{6x-2y=-4} \atop {-4x+3y=-4}} \right.

In order to get terms to cancel out, multiply the top by 3 and bottom by 2

\left \{ {{18x-6y=-12} \atop {-8x+6y=-8}} \right.

The y values cancel out if you add the equations

10x = -20

x = -2

plug in x

6(-2) - 2y = -4

-12 - 2y = -4

-2y = 8

y = -4

Answer: B. (-2, -4)

8 0
2 years ago
Show tan(???? − ????) = tan(????)−tan(????) / 1+tan(????) tan(????)<br> .
anyanavicka [17]

Answer:

See the proof below

Step-by-step explanation:

For this case we need to proof the following identity:

tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}

We need to begin with the definition of tangent:

tan (x) =\frac{sin(x)}{cos(x)}

So we can replace into our formula and we got:

tan(x-y) = \frac{sin(x-y)}{cos(x-y)}   (1)

We have the following identities useful for this case:

sin(a-b) = sin(a) cos(b) - sin(b) cos(a)

cos(a-b) = cos(a) cos(b) + sin (a) sin(b)

If we apply the identities into our equation (1) we got:

tan(x-y) = \frac{sin(x) cos(y) - sin(y) cos(x)}{sin(x) sin(y) + cos(x) cos(y)}   (2)

Now we can divide the numerator and denominato from expression (2) by \frac{1}{cos(x) cos(y)} and we got this:

tan(x-y) = \frac{\frac{sin(x) cos(y)}{cos(x) cos(y)} - \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{sin(x) sin(y)}{cos(x) cos(y)} +\frac{cos(x) cos(y)}{cos(x) cos(y)}}

And simplifying we got:

tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}

And this identity is satisfied for all:

(x-y) \neq \frac{\pi}{2} +n\pi

8 0
3 years ago
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