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3 years ago

Solve 5c + 4 = -26

1 answer:

6 0

1) 5 c + 4 = - 26
5 c = -26 -4
5 c = -30
c = -30 / 5
c = -6 so correct option is B..

2) 3 x - x +2 = 12
2 x +2 = 12
2x = 12-2
2x = 10
x = 10/2
x= 5 so correct option is D

3 ) 3 ( x + 1 )+ 6 = 33
3x + 3 + 6 = 33
3x + 9 = 33
3x = 33-9
3x = 24
x = 24/3
x = 8 so correct option is B

4) y/-6=9
y=9 x -6
y= - 54 there is no such option i guess question is missing

5)(x + 4) /2 = 7
x +4 = 7 x 2
x + 4 = 14
x = 14-4
x = 10 so correct option is D

6)1/3 ( 2x - 8) = 4
2x/ 3 - 8 /3 = 4
2x - 8 / 3 = 4
2x - 8 = 4 x 3
2x - 8 = 12
2x = 12 + 8
2x = 20
x = 20/2
x = 10 so correct option is C

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Whats 0 divide 0 i really want to know

Gelneren [198K]

Answer

N/A

Step-by-step explanation:

lets take a step into our imaginations, ok?

So when you divide, you're basically splitting the numerator into as many parts as the denominator.

imagine you have a chocolate bar, and it has 6 pieces and you want to split it evenly between your 3 friends.

you split it into three equal parts to get 2 pieces per person.

When you divide 0 by 0, your splitting 0 chocolate bars into 0 equal portions, which is why this problem isn't solvable.

4 0

3 years ago

Why do scientists use percentages less than 1

olganol [36]

They use percents less than one to get the the exact number

3 0

3 years ago

A building has a ramp to its front doors to accommodate the handicapped. If the distance from the building to the end of the ram

bija089 [108]

The ramp forms a right triangle with legs 5 and 22.
Find the length of the hypotenuse using the Pythagorean theorem,
c=raiz((5)^2+(22)^2)= 22.56 ft
Answer
 the ramp is 22.56 ft long.

7 0

2 years ago

From the given sides of 16, 14, and 21, determine what type of triangle it will form (right, acute, obtuse, none).

Komok [63]

Answer:

It is an acute triangle.

Step-by-step explanation:

It would be much easier for you to see where I'm getting at if you draw a diagram.

Assume this triangle is labelled ABC where a = 14, b = 21, and c = 16.

cos A = (16^2 + 21^2 - 14^2)/(2(16)(21))

∠A = cos^-1(0.82291...)

∠A ≅ 34.6°

cos B = 16^2 + 14^2 - 21^2)/(2(16)(14))

∠B = cos^-1(0.024...)

∠B ≅ 56.8°

∠C = 180 - (∠A + ∠B)

∠C ≅ 56.8°

Since there is no right-angle nor is there an obtuse angle,

Therefore the triangle is an acute triangle.

4 0

2 years ago

Average box of crackers is 24.5 ounces with standard deviation of. 8 ounce. What percent of the boxes weigh more than 22.9 ounce

34kurt

Answer:

97.7% of of the boxes weigh more than 22.9 ounces.

15.9% of of the boxes weigh less than 23.7 ounces.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24.5 ounces

Standard Deviation, σ = 0.8 ounce

We are given that the distribution of boxes weight is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(boxes weigh more than 22.9 ounces)

P(x > 22.9)

$P( x > 22.9) = P( z > \displaystyle\frac{22.9 - 24.5}{0.8}) = P(z > -2)$

$= 1 - P(z \leq -2)$

Calculation the value from standard normal z table, we have,

$P(x > 22.9) = 1 - 0.023 =0.977= 97.7\%$

97.7% of of the boxes weigh more than 22.9 ounces.

b) P(boxes weigh less than 23.7 ounces)

P(x < 23.7)

$P( x < 23.7) = P( z < \displaystyle\frac{23.7 - 24.5}{0.8}) = P(z < -1)$

Calculation the value from standard normal z table, we have,

$P(x < 23.7) =0.159= 15.9\%$

15.9% of of the boxes weigh less than 23.7 ounces.

7 0

3 years ago