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3 years ago

Find the image of (1,2) after a reflection about y=-1 followed by a reflection over y=1

Mathematics

1 answer:

lions [1.4K]3 years ago

4 0

Answer:

(1, 6).

Step-by-step explanation:

The reflection of the x coordinate of (1, 2) creates a point with y -coordinate

-1 - 3 = -4 while the x-coordinate remains 1.

The point (1, -4) is now reflected about y = 1, so -4 translates to 1 + 5 = 6. and x stays at 1.

Answer is (1, 6).

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Brainliest to first one.

masha68 [24]

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2 years ago

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How can I find the exact distance between the points(√7,-√2)and (4√7,5√2)

chubhunter [2.5K]

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \sqrt{7}}}\quad ,&{{ -\sqrt{2}}})\quad 
% (c,d)
&({{4\sqrt{7}}}\quad ,&{{ 5\sqrt{2}}})
\end{array}~~~
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
$

$\bf d=\sqrt{[4\sqrt{7}-\sqrt{7}]^2~+~[5\sqrt{2}-(-\sqrt{2})]^2}
\\\\\\
d=\sqrt{(4\sqrt{7}-\sqrt{7})^2~+~(5\sqrt{2}+\sqrt{2})^2}\implies d=\sqrt{(3\sqrt{7})^2~+~(6\sqrt{2})^2}
\\\\\\
d=\sqrt{3^2\cdot 7~~+~~6^2\cdot 2}\implies d=\sqrt{63+72}\implies d=\sqrt{135}
\\\\\\
\begin{cases}
135=5\cdot 3\cdot 3\cdot 3\\
\qquad 5\cdot 3^2\cdot 3\\
\qquad 15\cdot 3^2
\end{cases}\implies d=\sqrt{15\cdot 3^2}\implies d=3\sqrt{15}$

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3 years ago

Choose the option that best completes the statement. 1. A figure has symmetry with respect to a plane Z if for every point A of

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<span>1.perpendicular bisector.
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2 years ago

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Identify the initial amount a and the rate of growth r (as a percent) of the exponential function y = 12(1.05)t. Evaluate the fu

aleksandrvk [35]

Answer

Exponential function is in the form of : $y =a(1+r)^x$ .....[1]

where a is the initial amount and r is the growth rate and (1+r) is the growth factor.

Given the function: $y = 12(1.05)^t$

On comparing with equation [1] we have;

Initial amount(a) = 12

1+r = 1.05

Subtract 1 from both sides we get;

$r = 0.05$ or 5%

Growth (r) = 0.05 or 5%

Now, evaluate the function for t = 5 we have;

Substitute the value of t=5 in the given function we have;

$y = 12(1.05)^{5}$

$y = 12 \cdot 1.27628156 = 15.3153787$

Therefore, the value of function when t=5 to the nearest tenth is 15.3

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2 years ago

Suppose a runner completes a 100-meter dash in 17.8 seconds during her first race. In the second race, she runs the 100-meter da

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<span>We know that the runner completed her first race in 17.8 seconds and that she completed her second race in 16.9 seconds. Then the difference between the first race and the second race is .9 seconds. Now we divide .9 by 17.8 and multiply by 100 to get the percent decrease. We get 5.06%. The percent decrease in her time is 5%.</span>

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3 years ago