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2 years ago

Identify true statements.

Mathematics

1 answer:

prisoha [69]2 years ago

8 0

Im not 100% sure but I think b is true

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The blue line is the graph of y=-4x + 5. Use the

WARRIOR [948]

Answer:

(1,1)

Step-by-step explanation:

1=-2(1)+3

1= -2 +3

1=1

1=-4(1)=5

1=-4=5

1=1

7 0

2 years ago

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1/3 + 5/6 + 5/12 What is the answer

SOVA2 [1]

1/3 + 5/6 + 5/12

1.583333333333333

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2 years ago

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Drinking eight fluid ounces of milk provides 270 mg of calcium. How many fluid ounces of milk provides 72.5 mg of calcium? Round

Vikentia [17]

A or C because you have to add some things but also divide.

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2 years ago

Answer the question in the picture

nekit [7.7K]

Recall the angle sum identities:

$\sin(x+y)=\sin x\cos y+\cos x\sin y$

$\cos(x+y)=\cos x\cos y-\sin x\sin y$

Now,

$\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\cos x\sin y}{\cos x\cos y-\sin x\sin y}$

Divide through numerator and denominator by $\cos x\cos y$ to get

$\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}$

Next, we use the fact that $x,y$ lie in the first quadrant to determine that

$\sin x=\dfrac12\implies\cos x=\sqrt{1-\sin^2x}=\dfrac{\sqrt3}2$

$\cos y=\dfrac{\sqrt2}2\implies\sin x=\sqrt{1-\cos^2x}=\dfrac1{\sqrt2}$

So we then have

$\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

$\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac1{\sqrt2}}{\frac{\sqrt2}2}=1$

Finally,

$\tan(x+y)=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3\approx3.73$

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2 years ago

**NO LINKS** Help please!<br><br>Need the value of both h and k

ANEK [815]

I have the same question that i don’t understand sorry i’m commenting so i can see if anyone else gets that answer

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2 years ago