All categories

3 years ago

Can someone pls help me with problems 4 and 5 pls this is due in a bit and I’m in a rush I’ll give 100 points it’s all I have

Mathematics

2 answers:

Talja [164]3 years ago

4 0

Answer:

Let M is the midpoint of DE.

Since D is at 8 and DE = 5.

DM = ME = 5/2 = 2.5

<u>Point M is at:</u>

8 + 2.5 = 10.5 if E is to the right of D
8 - 2.5 = 5.5 if E is to the left of D

<u>Given</u>

XY = 7,
YZ = 2x - 1,
XZ = 30

<u>Since XZ = XY + YZ, set up an equation and solve for x:</u>

7 + (2x - 1) = 30
2x + 6 = 30
2x = 24
x = 12

The distance from your house to friend's is LN.

M is midpoint of LN, so LM = MN
LM = 3x
MN = 2x + 2

<u>Set up an equation, solve for x:</u>

3x = 2x + 2
3x - 2x = 2
x = 2

<u>Find the distance LM:</u>

LM = 3*2 = 6

<u>Find the distance LN:</u>

LN = 2*LM = 2*6 = 12

alexandr402 [8]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

A survey of 700 adults from a certain region asked, "What do you buy from your mobile device?" The results indicated that 59%

Kryger [21]

Answer:

a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

c) 95% of confidence intervals are (0.523 ,0.596)

Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes $n_{1} = 400 and n_{2} = 300$

Proportion of mean $p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52$

<u>Null hypothesis H0</u> : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

<u>Alternative hypothesis H1:</u>- p1 ≠ p2

a) The test statistic is

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }$

where $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

on calculation we get p = 0.56

now q =1-p = 1-0.56=0.44

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }\\ =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300} }$

after calculation we get z = 1.891

b) The critical value at 95% confidence interval zα = 1.96 (from z-table)

The calculated z- value < the tabulated value

therefore the null hypothesis accepted

<u>conclusion</u>:-

assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) <u>95% confidence intervals</u>

The confidence intervals are P± 1.96(√PQ/n)

we know that = $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

on simplification we get (0.523 ,0.596)

Therefore the population proportion (0.56) lies in between the 95% of <u>confidence intervals (0.523 ,0.596)</u>

<u></u>

3 0

3 years ago

Find the measure of Q, the smallest angle in a triangle whose sides have lengths 4, 5, and 6. Round the measure to the nearest w

dsp73

Using SSS the given angles are 83, 56, and 41
41.41 is angle Q
41.41 so it's B

3 0

3 years ago

Read 2 more answers

he marketing research department at the Fresno Mall plans to survey teenagers about a newly developed soft drink. Each person sa

Nat2105 [25]

50% of those who liked orange flavored soda also like lime flavored soda according to the conditional probability.

According to the statement

we have given that the in the survey 70% of the people surveyed said they like the orange flavored soda and 35% of the people surveyed said they liked the orange flavored soda AND the lime flavored soda.

And we have to find the conditional probability about this given statement.

So, We know that the

Let A and B represents the following events.

A : The people like the orange flavored soda.

B : The people like the lime flavored soda.

It is given that 70% of the people surveyed said they like the orange flavored soda.

so, P(A) = 0.70

And 35% of the people surveyed said they liked the orange flavored soda AND the lime flavored soda.

So, P(A ∩ B ) = 0.35

A. Conditional probability is a measure of the probability of an event occurring, given that another event has already occurred.

And

B. The formula for conditional probability is is written below:

P(A/B) = P(A ∩ B ) / P (B)

And

C. We need to find the percent of those who liked orange flavored soda also like lime flavored soda.

Use the above written conditional probability formula then

Substitute P(A)=0.70 and P(A∩B)=0.35 in the above formula.

So,

P(B/A) = P(A ∩ B ) / P (A)

P(B/A) = 0.35 / 0.70

P(B/A) = 0.50

So, 50% of those who liked orange flavored soda also like lime flavored soda according to the conditional probability.

Learn more about conditional probability here

brainly.com/question/23382435

Disclaimer: This question was incomplete. Please find the full content below.

Question:

The marketing research department at the Fresno Mall plans to survey teenagers about a newly developed soft drink. 70% of the people surveyed said they like the orange flavored soda. 35% of the people surveyed said they liked the orange flavored soda AND the lime flavored soda. Using this information and the Text Editor, answer the following questions:

1.What is conditional probability?

2.Explain the formula for conditional probability.

3.Explain how to solve this example.

What percent of those who liked orange flavored soda also like lime flavored soda, and how did you come to that conclusion?

#SPJ4

5 0

1 year ago

Use the slope formula to determine the equation of the line (2,.75) and (4,.25)

guajiro [1.7K]

Answer:

y=-0.25x+1.25

Step-by-step explanation:

hope this helps u

6 0

3 years ago

4/5 n = 9/10<br>solve n

Alex787 [66]

N =9/8
n = 1 1/8

Hope this helpsb☺

6 0

3 years ago