The measure of the angle between the hypotenuse and the <em>short</em> leg is 60° and we can conclude that the side with length 10 is not the <em>long</em> leg of the 30 - 60 - 90 <em>right</em> triangle. (Right choice: False)
<h3>Is the length of a known arm in a 30 - 60 - 90 right triangle the long arm?</h3>
In accordance with geometry, the length of the <em>long</em> arm of a 30 - 60 - 90 <em>right</em> triangle is √3 / 2 times the length of the hypotenuse, the length of the <em>short</em> arm is 1 / 2 times the length of the hypotenuse and the length of the <em>long</em> arm is √3 times the length of the arm.
Thus, the measure of the angle between the hypotenuse and the <em>short</em> leg is 60° and we can conclude that the side with length 10 is not the <em>long</em> leg of the 30 - 60 - 90 <em>right</em> triangle. (Right choice: False)
To learn more on right triangles: brainly.com/question/6322314
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The given triangles are similar by ~
Answer:
f(x) = 4.35 +3.95·sin(πx/12)
Step-by-step explanation:
For problems of this sort, a sine function is used that is of the form ...
f(x) = A + Bsin(2πx/P)
where A is the average or middle value of the oscillation, B is the one-sided amplitude, P is the period in the same units as x.
It is rare that a tide function has a period (P) of 24 hours, but we'll use that value since the problem statement requires it. The value of A is the middle value of the oscillation, 4.35 ft in this problem. The value of B is the amplitude, given as 8.3 ft -4.35 ft = 3.95 ft. Putting these values into the form gives ...
f(x) = 4.35 + 3.95·sin(2πx/24)
The argument of the sine function can be simplified to πx/12, as in the Answer, above.
Answer:
it would be solved by it mom
