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Andrei [34K]
3 years ago
14

Find the distance between each pair of points E(-1, 0),F(12, 0)

Mathematics
1 answer:
Olegator [25]3 years ago
5 0

Answer:

The answer is

<h2>13 \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

<h3>d =  \sqrt{ ({x1 - x2})^{2}  +  ({y1 - y2})^{2} }  \\ </h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

E(-1, 0) and F(12, 0)

The distance between them is

<h3>|EF|  =  \sqrt{ ({ - 1 - 12})^{2}  +  ({0 - 0})^{2} }  \\  =  \sqrt{ ({ - 13})^{2} }  \\  =  \sqrt{169}</h3>

We have the final answer as

<h3>|EF| = 13 \:  \: units</h3>

Hope this helps you

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est scores for a statistics class had a mean of 79 with a standard deviation of 4.5. Test scores for a calculus class had a mean
Arte-miy333 [17]

Answer:

The z-score for the statistics test grade is of 1.11.

The z-score for the calculus test grade is 7.3.

Due to the higher z-score, the student performed better on the calculus test relative to the other students in each class

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

The grade with the higher z-score is better relative to the other students in each class.

Statistics:

Mean of 79 and standard deviation of 4.5, so \mu = 79, \sigma = 4.5

Student got 84, so X = 84

The z-score is:

Z = \frac{X - \mu}{\sigma}

Z = \frac{84 - 79}{4.5}

Z = 1.11

The z-score for the statistics test grade is of 1.11.

Calculus:

Mean of 69, standard deviation of 3.7, so \mu = 69, \sigma = 3.7

Student got 96, so X = 96

The z-score is:

Z = \frac{X - \mu}{\sigma}

Z = \frac{96 - 69}{3.7}

Z = 7.3

The z-score for the calculus test grade is 7.3.

On which test did the student perform better relative to the other students in each class?

Due to the higher z-score, the student performed better on the calculus test relative to the other students in each class

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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We simplify this by adding 6 and subtracting 6.

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