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bekas [8.4K]
3 years ago
14

Help me Solve 1/6 ÷ 2/6 please

Mathematics
1 answer:
pochemuha3 years ago
8 0
\frac{1}{6} ÷ \frac{2}{6}

First, apply this following rule: a ÷ \frac{b}{x} = a × \frac{c}{b}
\frac{1}{6} × \frac{6}{2}
Second, apply this following rule: \frac{a}{b} × \frac{c}{d} =  \frac{ac}{bd}
\frac{1x6}{6x2}
Third, multiply 1 × 6 to get 6 and 6 × 2 to get 12.
\frac{6}{12}
Fourth, find the GCF of 6 and 12. 
Factors of 6: 1, 2, 3, 6
Factors of 12: 1, 2, 3, 4, 6, 12
The GCF is 6.
Fifth, divide the numerator by the GCF.
6 ÷ 6 = 1
Sixth, divide the denominator by the GCF.
12 ÷ 6 = 2
Seventh, collect the new numerator and new denominator.
\frac{1}{2}

Answer as fraction: \frac{1}{2}
Answer as decimal: 0.5

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An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed
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Given

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Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

P(X = x) = \frac{y^xe^{-y}}{x!}

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

P(X\leq 1) = P(X=0) + P(X =1)

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}

P(X = 0) = \frac{1 * e^{-2.3}}{1}

P(X = 0) = e^{-2.3}

P(X = 0) = 0.10025884372

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P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}

P(X = 1) = \frac{2.3 * e^{-2.3}}{1}

P(X = 1) =2.3 * e^{-2.3}

P(X = 1) = 2.3 * 0.10025884372

P(X = 1) = 0.23059534055

P(X\leq 1) = P(X=0) + P(X =1)

P(X\leq 1) = 0.10025884372 + 0.23059534055

P(X\leq 1) = 0.33085418427

P(X\leq 1) = 0.331

Hence, the required probability is 0.331

6 0
2 years ago
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