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oksano4ka [1.4K]
3 years ago
9

Leyla drops a penny from a height of 150m.

Mathematics
1 answer:
dusya [7]3 years ago
5 0
Asked and answered elsewhere.
brainly.com/question/9071599
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Write an equation for the simple harmonic motion of a ball on a spring that starts at its lowest point of 6 inches below equilib
olasank [31]
So a general harmonic equation is Asin(2πt/T). Little t is just a variable. 6 inches is the height of one maximum and one minimum from equilibrium, so that is the amplitude A. T is the period, or the time of one cycle (or wavelength), which is 2 seconds.

The equation is therefore (in terms of seconds and inches), 6*sin(2πt/2), or 6*sin(πt).
6 0
3 years ago
Angles 1 and 2 are supplementary. 2 lines intersect to form angles 1 and 2. Which equation represents the relationship between t
mamaluj [8]

Answer:

\angle 1 + \angle 2 = 180^o

Step-by-step explanation:

Given

\angle 1 and \angle 2

Required

The relationship between them \angle 1 and \angle 2

From the question, we understand that \angle 1 and \angle 2 are supplementary

Supplementary angles add up to 180.

So, the relationship between \angle 1 and \angle 2 is:

\angle 1 + \angle 2 = 180^o

7 0
2 years ago
A recent survey based on a random sample of n=470 voters, predicted that independent candidate for the mayoral election will get
julsineya [31]

I have an expression

\sigma = \sqrt{p(1-p)/n}

floating around in my head; let's see if it makes sense.

The variance of binary valued random variable b that comes up 1 with probability p (so has mean p) is

E( (b-p)^2 ) =  (-p)^2(1-p) + (1-p)^2p = p(1-p)

That's for an individual sample. For the observed average we divide by n, and for the standard deviation we take the square root:

\sigma = \sqrt{p(1-p)/n}

Plugging in the numbers,

\sigma = \sqrt{.24(1-.24)/490} = 0.019 = 1.9\%

One standard deviation of the average is almost 2% so a 27% outcome was 3/1.9 = 1.6 standard deviations from the mean, corresponding to a two sided probability of a bit bigger than 10% of happening by chance.

So this is borderline suspect; most surveys will include a two sigma margin of error, say plus or minus 4 percent here, and the results were within those bounds.

7 0
3 years ago
Simplify without the absolute value |x+3| ; if x>2
inna [77]

Answer:

x+3 if x>2

Step-by-step explanation:

Recall some following basic ideas about absolute value:

|0|=0 or I guess -(0)=0

|3|=3

|-3|=-(-3) or just 3 but there is a reason why I wrote it the way I did.

You see that the absolute value returned the same value if the value was positive.

You see that the absolute value returned the opposite value if the value was negative.

You can include 0 in either.

Let's look at |x+3| alone for a second.

*|x+3|=x+3 if x+3 is positive or zero.

When is x+3 positive or zero? [greater than or equal to 0]

x+3\ge 0

Subtract 3 on both sides

x\ge -3

*|x+3|=-(x+3) if x+3 is negative or zero.

When is x+3 negative or zero? [less or equal to 0]

x+3\le 0

Subtract 3 on both sides

x\le -3

So looking at the bullet points (the *), x>2 fits into the first inequality.

Therefore, |x+3|=x+3.

8 0
3 years ago
use the factor theorem to find all the zeros of f(x)=2x^3+7x^2-77x-40 given that (x-5) is a factor of the polynomial
Soloha48 [4]
Because the factor would divide it into two
5 0
3 years ago
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